$$11 x+14 y=30 \text { and } 3 x+4 y=12$$ $$\begin{array}{cc}\text { Quantity } \mathbf{A} & \text { Quantity } \mathbf{B} \\ x+y & (x+y)^{-2} \end{array}$$ a. Quantity A is greater. b. Quantity B is greater. c. The two quantities are equal. d. The relationship cannot be determined from the information given.

Short Answer

Expert verified
The answer is (a). Quantity A is greater.

Step by step solution

01

Solve for the unknowns in the equations

Solving the system of equations \[11x + 14y = 30\] and \[3x + 4y = 12\] using substitution or elimination method gives the values of \(x = 2\) and \(y = 1\).
02

Substitute the values into Quantity A

Quantity A is expressed as \(x + y\). Substituting the solved values gives \(2+1\), which simplifies to \(3\).
03

Substitute the values into Quantity B

Quantity B is expressed as \((x + y)^{-2}\). Substituting the values \(2\) and \(1\) into the expression gives \((3)^{-2} = 1/9\).
04

Compare Quantity A and Quantity B

Comparing the results of Quantity A and Quantity B, \(3\) and \(1/9\) respectively, gives the insight that Quantity A is greater than Quantity B.

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