STATEMENT-1 : If \(A(1,2)\) and \(B(7,10)\) are two points. If \(P(x, y)\) is such that \(\angle A P B=60^{\circ}\), then area of \(\triangle \mathrm{APB}\) will be maximum if \(\mathrm{P}\) lies on \(L \equiv 3 x+4 y=16\) STATEMENT-2 : In statement-1 the area of triangle \(\mathrm{APB}\) is maximum if \(\mathrm{P}\) lies on the perpendicular bisector of \(\mathrm{AB}\). (1) Statement \(-1\) is True, Statement \(-2\) is True; Statement \(-2\) is a correct explanation for Statement \(-1\) (2) Statement- 1 is True, Statement-2 is True ; Statement- 2 is NOT a correct explanation for Statement- 1 (3) Statement \(-1\) is True, Statement \(-2\) is False (4) Statement \(-1\) is False, Statement \(-2\) is True

In coordinate geometry, the perpendicular bisector of a line segment is a line that divides the segment into two equal parts at 90 degrees. To find the perpendicular bisector of a line segment defined by two points, you need to:

• Calculate the midpoint of the segment.
• Determine the slope of the segment.
• Find the negative reciprocal of the segment's slope to get the slope of the perpendicular bisector.
• Formulate the equation of the line using the midpoint and the slope of the bisector.

For example, given points A(1, 2) and B(7, 10):
The midpoint M is \[ M = \left(\frac{1 + 7}{2}, \frac{2 + 10}{2}\right) = (4, 6) \] The slope of AB, m, is \[ m = \frac{10 - 2}{7 - 1} = \frac{8}{6} = \frac{4}{3} \] The slope of the perpendicular bisector is the negative reciprocal: \[ -\frac{3}{4} \] Plugging the midpoint and this slope into the point-slope form of the equation of a line, you get: \[ y - 6 = -\frac{3}{4}(x - 4) \] Simplifying this, you obtain the perpendicular bisector’s equation: \[ 3x + 4y = 36. \] Always make sure to recheck your calculations for correctness.

Understanding the slope of a line segment is crucial in coordinate geometry. The slope, or gradient, represents the direction and steepness of a line. For a segment between two points \((x_1, y_1)\) and \((x_2, y_2)\), the slope is calculated as: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] This formula tells you how much y changes for a unit change in x. For instance, for points A(1,2) and B(7,10):

• Subtract the y-values: \(y_2 - y_1 = 10 - 2 = 8\)
• Subtract the x-values: \(x_2 - x_1 = 7 - 1 = 6\)
• Divide the differences: \(m = \frac{8}{6} = \frac{4}{3} \)

The result, \(\frac{4}{3}\), means that for every 3 units of x increase, y increases by 4 units.
When dealing with perpendicular lines, remember that their slopes are negative reciprocals of each other. For instance, if a line’s slope is \(\frac{4}{3}\), the perpendicular line’s slope would be: \[-\frac{3}{4}\] Keep practicing with different coordinates to get comfortable with these calculations.

Finding the area of a triangle in coordinate geometry is a fundamental skill. For a triangle with vertices at \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\), the area can be calculated using the following determinant formula:
\[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| \] This formula arranges the coordinates in a specific pattern to compute the area. For a practical example, suppose you have points A(1,2), B(7,10), and P(x,y). To maximize the area of \(\triangle APB\), depending on further constraints (like keeping angle \(\angle APB = 60^\text{∘}\)), you might be required to ensure certain conditions are met. These conditions sometimes involve positioning P relative to specific geometric lines such as perpendicular bisectors, as discussed. Remember to always check your calculated area units and ensure you handle the absolute value to prevent negative area results.