Chapter 4: Problem 19
The value of \(\left({ }^{7} \mathrm{C}_{0}+{ }^{7} \mathrm{C}_{1}\right)+\left({ }^{7} \mathrm{C}_{1}+{ }^{7} \mathrm{C}_{2}\right)+\ldots \ldots+\) \(\left({ }^{7} \mathrm{C}_{6}+{ }^{7} \mathrm{C}_{7}\right)\) is (1) \(2^{8}-2\) (2) \(2^{8}-1\) (3) \(2^{8}+1\) (4) \(2^{8}\) (5) \(2^{7}-2\)
Short Answer
Expert verified
The value is \(2^8 - 2\), which is option (1).
Step by step solution
01
Understand the Problem
We need to find the sum of given binomial coefficients: \(\binom{7}{0} + \binom{7}{1}\), \(\binom{7}{1} + \binom{7}{2}\), up to \(\binom{7}{6} + \binom{7}{7}\).
02
Simplify Using Properties of Binomial Coefficients
Recall that \(\binom{n}{k} + \binom{n}{k+1} = \binom{n+1}{k+1}\). Split the problem into two separate sums: \((\binom{7}{0} + \binom{7}{1}) + (\binom{7}{1} + \binom{7}{2}) + \text{...} + (\binom{7}{6} + \binom{7}{7})\).
03
Sum Individual Pairs
Notice that each pair sums to \((\binom{7}{0} + \binom{7}{1}) + (\binom{7}{1} + \binom{7}{2}) + \text{...} + (\binom{7}{6} + \binom{7}{7})\), but the middle terms \(\binom{7}{1}, \binom{7}{2}, ..., \binom{7}{6}\) are added twice. Calculate \((\binom{7}{0} + 2\binom{7}{1} + 2\binom{7}{2} + 2\binom{7}{3} + 2\binom{7}{4} + 2\binom{7}{5} + 2\binom{7}{6} + \binom{7}{7})\).
04
Use Binomial Theorem
Notice the structure of the coefficients: \( \binom{7}{0} + \binom{7}{1} + \binom{7}{2} + \text{...} + \binom{7}{7} = 2^7\) from binomial theorem. Thus, the sum of the single terms is \(2^7\).
05
Calculate the Final Sum
The sum of individual pairs, with middle terms counted twice, is \(2^7 + \binom{7}{1} + \binom{7}{2} + \text{...} + \binom{7}{6}\). Simplify to find the sum is \(2 \times 2^7 - 2\), which is \(2^8 - 2\).
06
Match the Final Answer with the Options
Compare the result to provided options. The correct answer is (1) \(2^8 - 2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficients
Binomial coefficients are an essential part of combinatorics and are represented as \(\binom{n}{k}\). This notation expresses the number of ways to choose \('k'\) elements from a set of \('n'\) elements without regard to the order of selection.
Binomial coefficients can be calculated using the formula \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]
where \( n! \) (n factorial) represents the product of all positive integers up to \( n \). Here are some key points about binomial coefficients:
\
Understanding binomial coefficients helps in solving problems related to combinations and binomial expansions.
Binomial coefficients can be calculated using the formula \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]
where \( n! \) (n factorial) represents the product of all positive integers up to \( n \). Here are some key points about binomial coefficients:
\
- \
- They symmetric, meaning \( \binom{n}{k} = \binom{n}{n-k} \). \
- They are used in the expansion of binomial expressions. \
- They appear in Pascal's triangle where each entry is the sum of the two numbers directly above it. \
Understanding binomial coefficients helps in solving problems related to combinations and binomial expansions.
Binomial Expansion
The binomial expansion involves expanding expressions of the form \((a + b)^n\).
The Binomial Theorem provides a formula for this expansion:
\[ (a + b)^n = \binom{n}{0}a^n b^0 + \binom{n}{1}a^{n-1} b^1 + \binom{n}{2}a^{n-2} b^2 + \text{...} + \binom{n}{n}a^0 b^n \]
This theorem shows how a binomial expression can be expanded into a sum involving terms of the form \( a^k b^{n-k} \). Each term in the expansion is multiplied by a binomial coefficient, \( \binom{n}{k} \). Here's why this is useful:
\
For example, consider \( (1 + x)^7 = \binom{7}{0}1^7x^0 + \binom{7}{1}1^6x^1 + \text{...} + \binom{7}{7}1^0x^7 \). The coefficients here are the binomial coefficients, summing to create the expanded form.
The Binomial Theorem provides a formula for this expansion:
\[ (a + b)^n = \binom{n}{0}a^n b^0 + \binom{n}{1}a^{n-1} b^1 + \binom{n}{2}a^{n-2} b^2 + \text{...} + \binom{n}{n}a^0 b^n \]
This theorem shows how a binomial expression can be expanded into a sum involving terms of the form \( a^k b^{n-k} \). Each term in the expansion is multiplied by a binomial coefficient, \( \binom{n}{k} \). Here's why this is useful:
\
- \
- It simplifies the process of expanding polynomials. \
- It helps in calculating probabilities, especially in binomial distributions. \
- It is foundational in algebra and calculus. \
For example, consider \( (1 + x)^7 = \binom{7}{0}1^7x^0 + \binom{7}{1}1^6x^1 + \text{...} + \binom{7}{7}1^0x^7 \). The coefficients here are the binomial coefficients, summing to create the expanded form.
Combinatorics
Combinatorics is the branch of mathematics dealing with combinations, permutations, and the counting of objects.
It provides tools for solving problems that involve discrete structures and is vital in fields such as computer science, cryptography, and statistics.
Here are some foundational concepts in combinatorics:
\
Understanding combinatorics allows you to tackle complex problems involving counting and arrangements. In the exercise, you used combinatorial principles to simplify the sum of binomial coefficients and arrive at the final solution.
It provides tools for solving problems that involve discrete structures and is vital in fields such as computer science, cryptography, and statistics.
Here are some foundational concepts in combinatorics:
\
- \
- Permutations: Arrangements of objects in a specific order. Calculated using \( n! \) for \( n \) distinct objects. \
- Combinations: Selection of objects without regard to order. Involves binomial coefficients, as seen in the formula \( \binom{n}{k} \). \
- Principle of Inclusion-Exclusion: A method used to count the number of elements in overlapping sets. \
- Graph Theory: Studies graphs and networks to solve connectivity problems and optimize paths. \
Understanding combinatorics allows you to tackle complex problems involving counting and arrangements. In the exercise, you used combinatorial principles to simplify the sum of binomial coefficients and arrive at the final solution.