The reduction potential of hydrogen half cell will be negative if \((T=298 \mathrm{~K})\) (1) \(\mathrm{P}_{\mathrm{H}_{2}}=1 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}\) (2) \(\mathrm{P}_{\mathrm{H}_{2}}=2 \mathrm{~atm}\) and \(\left[\mathrm{H}^{*}\right]=2.0 \mathrm{M}\) (3) \(\mathrm{P}_{\mathrm{H}_{2}}=2 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}\) (4) \(\mathrm{P}_{\mathrm{H}_{2}}=1 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}\) (5) \(\mathrm{P}_{\mathrm{H}_{2}}=1 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=1.5 \mathrm{M}\)

Short Answer

Expert verified
Option 3: P_{H_2} = 2 atm and [H^+] = 1.0 M

Step by step solution

01

- Understanding the Nernst Equation

The reduction potential for a hydrogen half-cell can be determined using the Nernst equation: \[ E = E^\theta - \frac{0.0591}{n} \log \left( \frac{P_{H_2}}{[H^+]^2} \right), \] where: * \(E\) is the reduction potential. * \(E^\theta\) for the hydrogen half-cell is 0 V by definition. * \(P_{H_2}\) is the partial pressure of hydrogen gas in atm. * \([H^+]\) is the concentration of hydrogen ions in Molarity (M).* \(n\) is the number of electrons transferred, which is 2 for the hydrogen half-cell reaction.
02

- Calculate the Reduction Potential for Each Scenario

Substitute the values of \(P_{H_2}\) and \([H^+]\) for each given option into the Nernst equation and solve for \(E\):
03

- Option 1: Standard Conditions

For \(P_{H_2} = 1\, \text{atm}\) and \([H^+] = 1.0\, \text{M}\): \[ E = 0 - \frac{0.0591}{2} \log \left( \frac{1}{(1.0)^2} \right) = 0 \text{ V} \text{(Standard Conditions)}\]
04

- Option 2: Higher Pressure and Concentration

For \(P_{H_2} = 2\, \text{atm}\) and \([H^+] = 2.0\, \text{M}\): \[ E = 0 - \frac{0.0591}{2} \log \left( \frac{2}{(2.0)^2} \right) = 0 - \frac{0.0591}{2} \log (0.5) = 0 - 0.0591 \log (0.5) = 0 + 0.0591 \log (2) \approx 0.0178 \text{V} \]
05

- Option 3: Higher Pressure, Standard Concentration

For \(P_{H_2} = 2\, \text{atm}\) and \([H^+] = 1.0\, \text{M}\): \[ E = 0 - \frac{0.0591}{2} \log \left( \frac{2}{(1.0)^2} \right) = 0 - \frac{0.0591}{2} \log (2) \approx -0.0178 \text{V} \]
06

- Option 4: Standard Pressure, Higher Concentration

For \(P_{H_2} = 1\, \text{atm}\) and \([H^+] = 2.0\, \text{M}\): \[ E = 0 - \frac{0.0591}{2} \log \left( \frac{1}{(2.0)^2} \right) = 0 - \frac{0.0591}{2} \log (0.25) = 0 - 0.0591 \log (0.5) = 0 + 0.0591 \log (2) \approx 0.0178 \text{V} \]
07

- Option 5: Standard Pressure, Higher Concentration

For \(P_{H_2} = 1\, \text{atm}\) and \([H^+] = 1.5\, \text{M}\): \[ E = 0 - \frac{0.0591}{2} \log \left( \frac{1}{(1.5)^2} \right) = 0 - \frac{0.0591}{2} \log \left( \frac{4}{9} \right) = 0 + 0.0591 \log (4/3) \approx 0.020 \text{V} \]
08

- Identify the Scenario with Negative Potential

The reduction potential is negative when the calculated \(E\) value is negative. From the calculations, only option 3 gives a negative potential: \( E = -0.0178 \text{V} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrochemistry
Electrochemistry is the branch of chemistry that deals with the relationship between electrical energy and chemical changes. It involves studying how electrons move through a solution and how they cause chemical reactions. Understanding this process is key to grasping concepts like electrode potentials and galvanic cells. One of the fundamental tools in electrochemistry is the Nernst equation, which helps predict the potential of a cell under non-standard conditions. By measuring potentials, we can understand the energy changes that occur during reactions. Electrochemistry has many practical applications such as batteries, electroplating, and sensors.
Reduction Potential
Reduction potential represents a substance's tendency to gain electrons and be reduced. It's a vital concept in electrochemistry. The more positive the reduction potential, the greater the substance's ability to be reduced. In the context of the Nernst equation, the reduction potential under standard conditions \(E^\theta\) is impacted by temperature, ion concentration, and gas pressure. The equation is:
\[ E = E^\theta - \frac{0.0591}{n} \log \left( \frac{P_{H_2}}{[H^+]^2} \right) \]
Here, \(E^\theta\) is the standard electrode potential, \(n\) is the number of electrons involved, \(P_{H_2}\) is the pressure of hydrogen gas, and \[H^+\] is the concentration of hydrogen ions. By adjusting these variables, the potential changes, guiding us to understand whether a reaction is more or less favorable under specific conditions.
Hydrogen Half-Cell
The hydrogen half-cell is an essential reference in electrochemistry. It is often chosen as a standard for measuring and comparing electrode potentials. It consists of a platinum electrode in contact with \(1 \text{atm}\) hydrogen gas and an aqueous solution with \(1 \text{M}\) \[H^+\] ions. This setup is given a standard electrode potential of 0 V. The hydrogen half-cell can either act as an anode (oxidation) or cathode (reduction) depending on the other half-cell it is paired with. For any non-standard condition, the Nernst equation helps calculate its potential. This concept plays a crucial role in understanding and predicting the behavior of other electrochemical cells.

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