Let \(a, b, x\) and \(y\) be real numbers such that \(a-b=1\) and \(y \neq 0\). If the complex number \(z=x+i y\) satisfies \(\operatorname{Im}\left(\frac{a z+b}{z+1}\right)=\mathrm{y}\), then which of the following is(are) possible value(s) of \(x ?\) [A] \(-1+\sqrt{1-y^{2}}\) [B] \(-1-\sqrt{1-y^{2}}\) [C] \(1+\sqrt{1+y^{2}}\) [D] \(1-\sqrt{1+y^{2}}\)

Short Answer

Expert verified
After solving the equation obtained in Step 6, the possible values of \(x\) can be identified among the given options [A], [B], [C], or [D].

Step by step solution

01

- Substitute known values

First, substitute the known values into the given expression \(\operatorname{Im}\left(\frac{a z+b}{z+1}\right)=\mathrm{y}\). Here, \(z = x + iy\) and \(a-b = 1\), which gives us \(a = b + 1\).
02

- Put in terms of a and b

Now, replace \(a\) with \(b + 1\) in the expression to get \(\operatorname{Im}\left(\frac{(b+1)(x+iy)+b}{x+iy+1}\right) = y\).
03

- Simplify the expression

Simplify the expression: \(\operatorname{Im}\left(\frac{bx+b+y+ibx+iy^{2}+b}{x+iy+1}\right) = y\). Combine the real and imaginary parts to form \(\operatorname{Im}\left(\frac{(bx+b+y+iy^{2}+b) + i(bx+1)}{x+iy+1}\right) = y\).
04

- Remove the denominator

Multiply top and bottom of the fraction by the complex conjugate of the denominator to remove the complex number from the denominator: \(\operatorname{Im}\left(\frac{((bx+b+y+iy^{2}+b) + i(bx+1))(x-iy+1)}{(x+iy+1)(x-iy+1)}\right) = y\).
05

- Expand and simplify numerator

Expand the numerator and collect real and imaginary terms, then simplify the denominator by recognizing it's the modulus squared of \(z+1\): \(\operatorname{Im}\left(\frac{Numerator}{x^{2}+1}\right) = y\), where Numerator is the expanded form of the multiplied terms in the previous step.
06

- Obtain the imaginary part

The imaginary part of the expression is obtained by equating the coefficient of \(i\) in the numerator to \(y * (x^2 + 1)\). This equation will now be solved for \(x\).
07

- Solve for x

At this point, you have an equation involving \(x\), \(y\), and the known value of \(b\). Solve this equation for \(x\) to determine which of the provided options [A] through [D] are possible values for \(x\) given the initial constraints.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Part of Complex Numbers
The imaginary part of a complex number is critical to understanding complex number algebra. When dealing with complex numbers, such as in the expression \( z = x + iy \), the 'imaginary part' refers to the coefficient of the imaginary unit \(i\) — in this case, \(y\). Imaginary units are defined by the property that \(i^2 = -1\).

The given exercise involves isolating the imaginary part after manipulating the complex expression \( \frac{a z + b}{z + 1} \). The operation \( \operatorname{Im}(expression) \) signifies we are only interested in the coefficient of the imaginary unit \(i\) that appears after performing the complex algebra.
Complex Number Algebra
When working with complex numbers like \( z = x + iy \), it's essential to understand how to perform algebraic operations. In our problem, we are given an expression that mixes complex and real numbers, and one of our tasks is to simplify it using algebraic manipulation.

In this process, we first substitute known values, and then we strategically use the property that \( a - b = 1 \). Simplifying the expression and separating the real and imaginary parts is key. It's also important to multiply and divide by the complex conjugate, which, for a complex number \( z \), is \( \bar{z} = x - iy \) to eliminate the imaginary unit from the denominator. This step stabilizes the equation and sets up the next phase of the solution—extracting the imaginary part for comparison with the given \( y \). Through this process, students develop a deeper understanding of the operations involving complex numbers.
JEE Problem Solving
The Joint Entrance Examination (JEE) Advanced poses challenging problems that evaluate a student's grasp of various mathematical concepts—including those of complex numbers. To excel in JEE problem-solving, students should focus on a systematic approach: start by understanding the problem, identify what is known and what is to be found, and carefully carry out step-by-step algebraic manipulations.

For instance, in this problem, we are tasked with finding possible values of \( x \) given a condition related to the imaginary part of a complex expression. The solution involves patience and precision—substituting values, simplification, and thoughtful consideration in equating the imaginary parts. It encapsulates the JEE exam's objective of testing a student's ability to apply mathematical theory to complex and multifaceted problems.

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