Chapter 14: Problem 63
The empty space in this HCP unit cell is (A) \(74 \%\) (B) \(47.6 \%\) (C) \(32 \%\) (D) \(26 \%\)
Short Answer
Expert verified
The empty space in the HCP unit cell is 100% - 74% = 26%.
Step by step solution
01
Define the HCP Structure
The Hexagonal Close-Packed (HCP) structure has a packing efficiency of approximately 74%. The packing efficiency is the percentage of volume in a unit cell that is occupied by the atoms. Therefore, the empty space can be found by subtracting this value from 100%.
02
Calculate the Empty Space Percentage
Subtract the packing efficiency from 100% to find the percentage of the unit cell that is empty space. The formula for this calculation is: Empty Space (%) = 100% - Packing Efficiency (%).
03
Substitute the Known Value
Using the known packing efficiency for a HCP structure, perform the calculation: Empty Space (%) = 100% - 74%.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Packing Efficiency in Unit Cells
Imagine lining up spheres, such as atoms, in the tightest possible arrangement; this is what we refer to as 'packing'. Now, when we talk about packing efficiency, we're measuring how much space these spheres occupy within a unit cell. Imagine a box filled with tennis balls - the more tennis balls we can fit inside without any gaps, the higher the packing efficiency will be.
In the context of crystal structures, like those found in metals and salts, a high packing efficiency means the atoms are closely packed to one another, leaving minimal empty space. This efficiency is calculated as the ratio of the combined volume of the spheres to the total volume of the unit cell, typically expressed as a percentage. In a hexagonal close-packed (HCP) structure, atoms are stacked in such a way that each atom is surrounded by six others, forming a hexagonal arrangement. This gives it a packing efficiency of around 74%, which is among the highest efficiency levels for any crystal structure.
Understanding this concept is crucial because the packing efficiency has a direct impact on the properties of a material, including its density and stability. Materials with high packing efficiencies, like certain metals, tend to be denser and less compressible.
In the context of crystal structures, like those found in metals and salts, a high packing efficiency means the atoms are closely packed to one another, leaving minimal empty space. This efficiency is calculated as the ratio of the combined volume of the spheres to the total volume of the unit cell, typically expressed as a percentage. In a hexagonal close-packed (HCP) structure, atoms are stacked in such a way that each atom is surrounded by six others, forming a hexagonal arrangement. This gives it a packing efficiency of around 74%, which is among the highest efficiency levels for any crystal structure.
Understanding this concept is crucial because the packing efficiency has a direct impact on the properties of a material, including its density and stability. Materials with high packing efficiencies, like certain metals, tend to be denser and less compressible.
Hexagonal Close-Packed Structure
Delving into the hexagonal close-packed structure, it's essential to visualize each layer of hexagonal-packed atoms like a tightly packed honeycomb. Each cell in the honeycomb is surrounded by neighbors, minimizing empty space. This HCP structure is one of the ways to pack spheres in the most space-efficient manner.
An HCP unit cell is a hexagonal prism composed of two hexagonal bases and six rectangular faces. In three dimensions, atoms are arranged so each is at a vertex of a regular tetrahedron, with one atom in the center of the tetrahedron. This structure is prevalent in many metals, such as magnesium and titanium, due to its high packing efficiency and the stability it confers to the atomic arrangement.
The concept of atomic packing is also critical for understanding a material’s strength and how it deforms under stress. In HCP materials, the directional bonds in this arrangement offer resistance to deformation, which is why many HCP metals are known for their hardness and durability.
An HCP unit cell is a hexagonal prism composed of two hexagonal bases and six rectangular faces. In three dimensions, atoms are arranged so each is at a vertex of a regular tetrahedron, with one atom in the center of the tetrahedron. This structure is prevalent in many metals, such as magnesium and titanium, due to its high packing efficiency and the stability it confers to the atomic arrangement.
The concept of atomic packing is also critical for understanding a material’s strength and how it deforms under stress. In HCP materials, the directional bonds in this arrangement offer resistance to deformation, which is why many HCP metals are known for their hardness and durability.
Volume Calculation of the HCP Unit Cell
When it comes to volume calculation for a hexagonal close-packed unit cell, it's necessary to use geometry and algebra. The unit cell of an HCP structure can be considered as two parts: a hexagonal prism, and a half of a hexagonal prism that captures the atoms in the staggered layers.
The volume of the hexagonal prism can be found with the formula: Volume = Area of Base × Height. The area of the hexagonal base is determined by splitting the hexagon into equilateral triangles and calculating their combined area; for an equilateral triangle, the area is \( \frac{\sqrt{3}}{4} \times a^2 \), where \( a \) is the side length. Since there are six triangles in a hexagon, we scale this area by six. The height corresponds to the distance between two consecutive hexagonal layers.
To account for the entire mass of the atoms and the full unit cell, one must consider the placement and radius of the atoms to ascertain occupied volume. Remembering that the actual volume occupied by atoms is determined by their spherical shape, you apply the sphere's volume formula, which is \( \frac{4}{3}\pi r^3 \) for each atom, where \( r \) is the atomic radius. By adding up the respective volumes of atoms fitting in the unit cell, you can calculate the total volume occupied by atoms.
The volume of the hexagonal prism can be found with the formula: Volume = Area of Base × Height. The area of the hexagonal base is determined by splitting the hexagon into equilateral triangles and calculating their combined area; for an equilateral triangle, the area is \( \frac{\sqrt{3}}{4} \times a^2 \), where \( a \) is the side length. Since there are six triangles in a hexagon, we scale this area by six. The height corresponds to the distance between two consecutive hexagonal layers.
To account for the entire mass of the atoms and the full unit cell, one must consider the placement and radius of the atoms to ascertain occupied volume. Remembering that the actual volume occupied by atoms is determined by their spherical shape, you apply the sphere's volume formula, which is \( \frac{4}{3}\pi r^3 \) for each atom, where \( r \) is the atomic radius. By adding up the respective volumes of atoms fitting in the unit cell, you can calculate the total volume occupied by atoms.