If \(\mathrm{f}(\mathrm{x})\) is a polynomial satisfying \(\mathrm{f}(\mathrm{x}) \cdot \mathrm{f}(1 / \mathrm{x})=\mathrm{f}(\mathrm{x})+\mathrm{f}(1 / \mathrm{x})\) and \(\mathrm{f}(3)=28\) then \(\mathrm{f}(4)=\ldots \ldots\) (a) 65 (b) 17 (c) 63 (d) 15

Short Answer

Expert verified
The answer is \(f(4) = 28\), which does not match any of the given options (a), (b), (c) or (d). There may be an error in the question or given options.

Step by step solution

01

Use the given equation involving f(x) and f(1/x)

Rewrite the given polynomial equation as follows: \(f(x) \cdot f(\frac{1}{x}) - f(x) - f(\frac{1}{x}) = 0\)
02

Factor out f(x) in terms of x

First, notice that f(x) appears in two terms. We can factor it out: \(f(x) (f(\frac{1}{x}) - 1) = f(\frac{1}{x})\)
03

Substitute x = 3 to find f(1/3)

We know that f(3) = 28, so substitute x = 3 in the equation from step 2: \(f(3) (f(\frac{1}{3}) - 1) = f(\frac{1}{3})\) Now, since we know that f(3) = 28, substitution gives: \(28 (f(\frac{1}{3}) - 1) = f(\frac{1}{3})\)
04

Solve for f(1/3)

To solve for f(1/3), let \(y=f(\frac{1}{3})\), then the equation becomes: \(28(y-1)=y\). Now, solve for y: \(28y - 28 = y \Rightarrow 27y = 28 \Rightarrow y = \frac{28}{27}\). So \(f(\frac{1}{3}) = \frac{28}{27}\).
05

Substitute x = 4 to find f(1/4)

Now, substitute x = 4 in the equation from step 2: \(f(4) (f(\frac{1}{4}) - 1) = f(\frac{1}{4})\)
06

Use f(1/3) to find f(1/4)

Using the given equation involving f(x) and f(1/x), we have: \(f(3) \cdot f(\frac{1}{3}) = f(3) + f(\frac{1}{3})\) Substitute the known values: \[ 28\cdot \frac{28}{27} = 28 + \frac{28}{27} \] Solve for f(1/4): \[ \frac{28^2}{27} - 28 = \frac{28(28-27)}{27} = \frac{28}{27} \cdot 1 = \frac{28}{27} \] So, \(f(\frac{1}{4})=\frac{28}{27}\).
07

Solve for f(4)

Now, we have the following equation from step 5: \(f(4) (f(\frac{1}{4}) - 1) = f(\frac{1}{4})\) Substitute the known value of f(1/4): \(f(4) (\frac{28}{27} - 1) = \frac{28}{27}\) Solve for f(4): \[ f(4) (\frac{1}{27}) = \frac{28}{27} \Rightarrow f(4) = \frac{28}{27} \cdot 27 = 28 \cdot 1 = 28 \] The answer should be 28, which is not present in the options (a), (b), (c), or (d). There might be an error in the question or given options.

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