\(\int \mathrm{e}^{4 \log \mathrm{x}}\left(\mathrm{x}^{5}+1\right)^{-1}=\underline{\mathrm{c}}\) (a) \((1 / 5) \log \left(\mathrm{x}^{4}+1\right)\) (b) \(-\log \left(\mathrm{x}^{4}+1\right)\) (c) \(\log \left(x^{4}+1\right)\) (d) \((1 / 5) \log \left(x^{5}+1\right)\)

Short Answer

Expert verified
(d) \(\frac{1}{5}\log\left(x^5 + 1\right)\)

Step by step solution

01

Simplify the integrand

Apply the logarithm properties of \(\exp\) and \(\log\). Since \(\mathrm{e}^{4\log\mathrm{x}} = \mathrm{x}^4\), we can rewrite the given integral as: \[\int \mathrm{x}^4\left(\mathrm{x}^{5}+1\right)^{-1}\,\mathrm{d}x\]
02

Integrate using substitution

Let us perform a substitution: \[u = x^5 + 1\] \[ \frac{\mathrm{d}u}{\mathrm{d}x} = 5x^4\] \[\mathrm{d}u = 5x^4\mathrm{d}x\] Substituting into the integral: \[\int \frac{1}{5}\cdot\frac{\mathrm{d}u}{u}\]
03

Integrating

Now we can easily integrate the expression: \[\frac{1}{5} \int \frac{\mathrm{d}u}{u}\] The integral of \(1/u \mathrm{d}u\) is \(\log(|u|) + C\), so our final expression will be: \[\frac{1}{5}\log(|u|) + C\]
04

Reverse substitution

Substitute the original variable \(x\) back in: \[\frac{1}{5}\log(x^5 + 1) + C\] Comparing the options given, it matches with option (d): \(\boxed{\text{(d) }\frac{1}{5}\log\left(x^5 + 1\right)}\)

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