Chapter 14: Problem 1305
Three straight lines \(2 \mathrm{x}+11 \mathrm{y}-5=0,4 \mathrm{x}-3 \mathrm{y}-2=0\) and \(24 x+7 y-20=0\) (a) form a triangle (b) are only concurrent (c) are concurrent with one line bisecting the angle between the other two. (d) none of these
Short Answer
Expert verified
The given lines do not form a triangle, are not concurrent, and none of the lines bisect the angle between the other two. Therefore, the answer is \((d)\) none of these.
Step by step solution
01
Find the point of intersection (concurrency) of the given lines
Let's consider the two lines:
\(2x + 11y = 5\), and \(4x - 3y = 2\).
To find the point of intersection, we need to solve them simultaneously by finding the values of x and y that satisfy both equations.
To do this, first solve for x from one of the equations and substitute it into the other equation. We can solve for x from the first equation:
\(x = \frac{5 - 11y}{2}\)
Now substitute this x into the second equation:
\(4\left(\frac{5 - 11y}{2}\right) - 3y = 2\)
Solve for y:
\(20 - 44y - 6y = 4\)
\(-50y = -16\)
\(y = \frac{16}{50}=\frac{8}{25}\)
Now substitute the value of y back into the equation for x:
\(x = \frac{5 - 11(\frac{8}{25})}{2}\)
\(x = \frac{5\cdot 25 - 11 \cdot 8}{25\cdot 2}\)
\(x = \frac{125 - 88}{50}\)
\(x = \frac{37}{50}\)
The point of intersection (concurrency) is \(\left(\frac{37}{50}, \frac{8}{25}\right)\).
02
Determine if lines form a triangle
Lines form a triangle if they don't have a common point of intersection (concurrency), and in this case, we have found a point of concurrency for the first two lines. Now let's check if the third line passes through this point:
\(24x + 7y = 20\)
Plug in the point of intersection \(\left(\frac{37}{50}, \frac{8}{25}\right)\):
\(24\left(\frac{37}{50}\right) + 7\left(\frac{8}{25}\right) = 20\)
\(\frac{888 + 56}{50} = 20\)
\(\frac{944}{50} ≠ 20\)
Thus, the three lines do not form a triangle since the last line doesn't pass through the point of intersection of the first two lines.
03
Determine if lines are concurrent
We have determined that the given lines are concurrent since the first two lines intersect at a single point. However, once we evaluate the third line at this point, we find that line doesn't pass through it, meaning that the lines are not concurrent.
04
Determine if one line bisects the angle between the other two
Since we already know that the lines are neither concurrent nor forming a triangle, we can conclude that the answer is (d) none of these.
So the answer is:
(d) none of these.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Systems of Linear Equations
When we discuss systems of linear equations, we're looking at sets of equations that share common solutions. These equations represent lines in a two-dimensional space. When two or more lines intersect at a single point, this point is a shared solution to the system, meaning that it satisfies all equations involved.
To solve a system of linear equations, one can use various methods such as substitution, elimination, or graphing. The method of substitution involves isolating one variable and substituting its value in the other equations. This is what we saw in the textbook exercise, where the solution for 'x' from the first equation was substituted into the second to find 'y'.
To solve a system of linear equations, one can use various methods such as substitution, elimination, or graphing. The method of substitution involves isolating one variable and substituting its value in the other equations. This is what we saw in the textbook exercise, where the solution for 'x' from the first equation was substituted into the second to find 'y'.
- Substitution helps to reduce a two-variable system to a single variable equation.
- Concurrent lines are lines in a system that all intersect at a single point.
- The point of concurrency is the point where the lines meet; it is the common solution to all equations in a system.
Points of Intersection
Points of intersection are exactly what they sound like: they're the points where two or more lines or curves meet on a graph. They are significant in geometry and algebra because they represent the solutions where all equations or functions involved agree.
Finding the points of intersection between two linear equations, as seen in our textbook problem, can be done algebraically or graphically. Algebraically, we solve the equations together as a system; graphically, we would plot both lines and observe where they cross.
Finding the points of intersection between two linear equations, as seen in our textbook problem, can be done algebraically or graphically. Algebraically, we solve the equations together as a system; graphically, we would plot both lines and observe where they cross.
Significance of Points of Intersection
Points of intersection can indicate:- The exact answers to systems of equations.
- Possible areas of agreement or conflict in real-world scenarios modeled by equations.
- Geometric relations such as concurrency, parallelism, or the shape of polygons formed by lines.
Geometry in Algebra
The study of geometry in algebra involves translating geometric concepts into algebraic equations and vice versa. It allows us to solve geometric problems using algebraic methods, such as finding the area of shapes, the equations of lines, and the points of intersection.
Geometry can provide a visual understanding of algebraic principles. For example, the concept of concurrent lines, which are lines that all intersect at a single point, ties directly into the notion of systems of linear equations in algebra. The geometry of these lines helps visualize their relationships and the concept of a solution to a system.
Geometry can provide a visual understanding of algebraic principles. For example, the concept of concurrent lines, which are lines that all intersect at a single point, ties directly into the notion of systems of linear equations in algebra. The geometry of these lines helps visualize their relationships and the concept of a solution to a system.
Geometric Principles in Algebraic Form
- In algebra, the perpendicular bisector of a line segment can be found by deriving its equation.
- The angle bisectors in a triangle can be represented as lines, each with its own equation.
- A polygon formed by lines can be dissected into triangles and rectangles, whose areas can be found using algebra.