Chapter 15: Problem 1378
A circle is given by \(\mathrm{x}^{2}+(\mathrm{y}-1)^{2}=1\), another circle \(\mathrm{C}\) touches it externally and also the \(\mathrm{x}\) -axis, then the locus of its centre is \(\ldots \ldots \ldots\) (a) \(\left\\{(\mathrm{x}, \mathrm{y}): \mathrm{x}^{2}=4 \mathrm{y}\right\\}\\{(\mathrm{x}, \mathrm{y}): \mathrm{y}=0\\}\) (b) \(\left\\{(\mathrm{x}, \mathrm{y}): \mathrm{x}^{2}+(\mathrm{y}-1)^{2}=4\right\\}\\{(\mathrm{x}, \mathrm{y}): \mathrm{y}=0\\}\) (c) \(\left\\{(\mathrm{x}, \mathrm{y}): \mathrm{x}^{2}=\mathrm{y}\right\\} \quad\\{(0, \mathrm{y}): \mathrm{y}=0\\}\) (d) \(\left\\{(x, y): x^{2}=4 y\right\\}\\{(0, y): y=0\\}\)
Short Answer
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Key Concepts
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