Chapter 15: Problem 1409
If \(\mathrm{x}+\mathrm{y}+1=0\) touches the parabola \(\mathrm{y}^{2}=\mathrm{ax}\) then \(\mathrm{a}=\ldots \ldots \ldots\) (a) 8 (b) 6 (c) 4 (d) 2
Short Answer
Expert verified
The correct answer is (c) 4, which is obtained by finding the tangent to the parabola, equating the slopes of the tangent and the given line, and solving the resulting quadratic equation for the value of 'a'.
Step by step solution
01
Understand the given information
We are given that a line with equation x + y + 1 = 0 touches the parabola with equation y^2 = ax. Our task is to determine the value of 'a'.
02
Find the slope of the given line
The given line is x + y + 1 = 0. Rewrite the equation in the form y = mx + c, where m is the slope and c is the y-intercept. The equation becomes y = -x - 1, where the slope m = -1.
03
Write down the equation of the tangent to the parabola
To find the tangent to the parabola y^2 = ax, we differentiate the equation with respect to x to obtain the slope of the tangent.
Differentiate y^2 = ax using the chain rule: \[\frac{d}{dx}(y^{2})=\frac{d}{dx}(ax)\], which gives: \[2y \frac{dy}{dx} = a\].
Now, divide by 2y to find the slope of the tangent: \[\frac{dy}{dx} = \frac{a}{2y}\].
04
Equate the slopes of the tangent and the given line
The slopes of the tangent to the parabola and the given line are equal as they touch each other. Therefore, we can set the slopes equal and solve for 'a'.
Equating the slopes, we have: \[-1 = \frac{a}{2y}\]
05
Solve for 'a'
From the above equation, we can solve for 'a' by multiplying both sides by 2y:
\[-2y = a\]
Now, substitute the equation of the given line (y = -x - 1) into the above equation: \[-2(-x - 1) = a\]
06
Simplify the equation
Simplify the equation to find the value of 'a':
\[2x + 2 = a\]
This equation tells us that 'a' is a function of 'x.' However, we are looking for a constant value of 'a' based on the given options. Thus, we need to further evaluate this equation.
07
Substitute the parabola equation into the line equation
To eliminate the dependency on 'x,' we need to substitute the parabola equation into the given line equation.
From the parabola equation y^2 = ax, we know that x = (y^2)/a. Substitute this into the line equation: \[\frac{y^2}{a} + y + 1 = 0\]
08
Find the discriminant of the quadratic equation
Since the line touches the parabola at only one point, the discriminant of the quadratic equation is equal to 0.
The discriminant (D) of a quadratic equation is given by the formula: \[D = B^2 - 4AC\]
In our case, A = 1/a, B = 1, and C = 1. Plug these values into the discriminant formula: \[D = 1^2 - 4\left(\frac{1}{a}\right)(1) = 0\]
09
Solve for 'a'
Now we have a quadratic equation in terms of 'a':
\[1 - \frac{4}{a} = 0\]
Solve for 'a' by adding 4/a to both sides: \[\frac{4}{a} = 1\]
Now, multiply both sides by 'a' to find the value of 'a': \[a = 4\]
10
Determine the correct answer
By solving the system of equations, we found out that a = 4 (option c). Therefore, the correct answer is:
(c) 4
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant of Quadratic Equation
When dealing with quadratic equations, the discriminant is a powerful tool that tells us about the nature of the roots without actually solving the equation. Given a quadratic equation in the standard form \( ax^2 + bx + c = 0 \), the discriminant \( D \) is given by the expression \( D = b^2 - 4ac \).
The value of the discriminant reveals whether the quadratic equation has two distinct real roots (if \( D > 0 \) ), one repeated real root (if \( D = 0 \) ), or no real roots (if \( D < 0 \) ). In the context of a line tangent to a parabola, a discriminant of zero means that the line just touches the parabola at one point and does not cross it, indicating a perfect tangent. Students should remember that when they find a discriminant equal to zero, they can be confident that there's precisely one point of tangency between the line and the quadratic curve.
The value of the discriminant reveals whether the quadratic equation has two distinct real roots (if \( D > 0 \) ), one repeated real root (if \( D = 0 \) ), or no real roots (if \( D < 0 \) ). In the context of a line tangent to a parabola, a discriminant of zero means that the line just touches the parabola at one point and does not cross it, indicating a perfect tangent. Students should remember that when they find a discriminant equal to zero, they can be confident that there's precisely one point of tangency between the line and the quadratic curve.
Slope of a Line
The slope of a line is a measure of its steepness, often denoted as \( m \). In the coordinate plane, it can be calculated as the change in \( y \) divided by the change in \( x \) between two distinct points on the line. The slope is fundamental when studying lines because it allows us to determine the angle and direction of a line, as well as to find equations of lines. A positive slope means the line ascends from left to right, while a negative slope means it descends. A horizontal line has a slope of zero, and a vertical line's slope is undefined because the change in \( x \) is zero, which would make the calculation involve division by zero.
When a line is said to be tangent to a curve, such as a parabola, the slope of the line at the point of tangency is equal to the slope of the tangent to the curve at that same point. This is key to solving problems like finding a specific value that will make a line tangent to a parabolic shape.
When a line is said to be tangent to a curve, such as a parabola, the slope of the line at the point of tangency is equal to the slope of the tangent to the curve at that same point. This is key to solving problems like finding a specific value that will make a line tangent to a parabolic shape.
Differentiation of Parametric Equations
Differentiation of parametric equations involves finding the rate of change in terms of a parameter, which typically represents time or some other variable that both expressions are dependent upon. Unlike traditional functions where \( y \) is expressed explicitly in terms of \( x \) (i.e., \( y = f(x) \) ), parametric equations define both \( x \) and \( y \) in terms of a third variable, often denoted as \( t \).
To differentiate parametric equations \( x = f(t) \) and \( y = g(t) \), you compute \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \) separately. Then, to find the slope of the tangent line at a particular point, you use the ratio \( \frac{dy/dt}{dx/dt} \), which gives you \( \frac{dy}{dx} \). When working with curves defined parametrically, such as parabolas or ellipses, understanding how to differentiate with respect to a parameter is crucial to determining the nature of the curve at any given point, which is especially important for identifying slopes of tangents, areas, or lengths related to the shape.
To differentiate parametric equations \( x = f(t) \) and \( y = g(t) \), you compute \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \) separately. Then, to find the slope of the tangent line at a particular point, you use the ratio \( \frac{dy/dt}{dx/dt} \), which gives you \( \frac{dy}{dx} \). When working with curves defined parametrically, such as parabolas or ellipses, understanding how to differentiate with respect to a parameter is crucial to determining the nature of the curve at any given point, which is especially important for identifying slopes of tangents, areas, or lengths related to the shape.