Chapter 18: Problem 694
The sum of the squares of deviation for 10 observations taken from their mean 30 is 90 . The coefficient of variation is (a) \(20 \%\) (b) \(10 \%\) (c) \(11 \%\) (d) \(12 \%\)
Chapter 18: Problem 694
The sum of the squares of deviation for 10 observations taken from their mean 30 is 90 . The coefficient of variation is (a) \(20 \%\) (b) \(10 \%\) (c) \(11 \%\) (d) \(12 \%\)
All the tools & learning materials you need for study success - in one app.
Get started for free\(A\) and \(B\) are events of same experiments with \(P(A)=0.2\) \(P(B)=0.5\) Maximum value of \(P\left(A^{\prime} \cap B\right)=\) (a) \(0.2\) (b) \(0.5\) (c) \(0.1\) (d) \(0.4\)
For 100 observations \(\sum(x i-30)=0\) and \(\sum(x i-30)^{2}=10000\) then C.V. (coefficient of variance) is \(\%\) (a) 10 (b) 100 (c) \(33.33\) (d) 30
Suppose a population \(A\) has 50 observations \(101,102, \ldots \ldots . .150\) and another population \(\mathrm{B}\) has 50 observations \(201,202, \ldots \ldots \ldots 250\). If \(\mathrm{V}_{\mathrm{A}}\) and \(\mathrm{V}_{\mathrm{B}}\) represent the variance of the two populations respectively then \(\left(\mathrm{V}_{\mathrm{A}} / \mathrm{V}_{\mathrm{B}}\right)\) is (a) 1 (b) \((2 / 3)\) (c) \((3 / 2)\) (d) \((9 / 4)\)
A and B throws a dice. The probability that A wins, if he throws a number higher than \(\mathrm{B}\) is (a) \((1 / 2)\) (b) \((15 / 36)\) (c) \((1 / 36)\) (d) None
Four numbers are multiplied together. Probability that the product is divisible by 5 or 10 is (a) \((369 / 625)\) (b) \((324 / 625)\) (c) \((16 / 625)\) (d) \((369 / 1000)\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.