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Chapter 18: Problem 698
If the variance of \(\mathrm{x}\) is 4 then the variance of \(3+5 \mathrm{x}\) is (a) 100 (b) 103 (c) 20 (d) 23
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For observations \(x_{1}, x_{2}, \ldots \ldots . . x_{n}, n_{i=1}(x i+4)=100\) and \(n_{i=1}(x i+6)=140\) then \(n=\) and \(\underline{x}=\) (a) 3,20 (b) 20,3 (c) 1,20 (d) 20,1
10 balls are distributed among three boxes. Probability that the first box will contain 3 balls is (a) \(\left[\left({ }^{10} \mathrm{C}_{3} \times 2^{7}\right) / 3^{10}\right]\) (b) \(\left[\left({ }^{10} \mathrm{C}_{3} \times 2^{7}\right) / 10^{3}\right]\) (c) \(\left[\left({ }^{10} \mathrm{C}_{3} \cdot{ }^{7} \mathrm{C}_{2}\right) / 3^{10}\right]\) (d) \(\left[\left({ }^{10} \mathrm{P}_{3} \cdot 2^{7}\right) / 3^{10}\right]\)
Mean of following frequency distribution is \(9.3\) then \(\mathrm{K}\) is $$ \begin{array}{|l|l|l|l|l|l|l|} \hline \mathrm{Xi} & 4 & 6 & 7 & \mathrm{~K} & 12 & 14 \\ \hline \mathrm{Fi} & 5 & 6 & 8 & 10 & 2 & 9 \\ \hline \end{array} $$ (a) 11 (b) 12 (c) 10 (d) 13
Two numbers from \(S=\\{1,2,3,4,5,6\\}\) are selected one by one without replacement. The probability that minimum of the two numbers is less than 4 is (a) \((1 / 15)\) (b) \((14 / 15)\) (c) \((1 / 5)\) (d) \((4 / 5)\)
If the mean and standard deviation of \(\mathrm{x}\) is \(\mathrm{b}\) and a respectively then the standard deviation of \([(x-b) / a]\) is (a) 1 (b) \((\mathrm{a} / \mathrm{b})\) (c) (b/a) (d) \(a b\)
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