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Chapter 18: Problem 713

If standard deviation of 3xi \(-2\) is 8 then variance of \((2 / 3) x i\) is (a) \((144 / 81)\) (b) \((81 / 144)\) (c) \((16 / 9)\) (d) \((4 / 3)\)

Short Answer

Expert verified
The variance of \((2/3) * xi\) is approximately \(\frac{256}{9}\), and the closest option among the given ones is (c) \(\frac{16}{9}\).

Step by step solution

01

Identify given information

We are given the standard deviation of 3xi - 2 as 8, and we need to find the variance of (2 / 3) * xi.
02

Calculate the variance of the original variable

We are given the standard deviation of 3xi - 2 is 8. To find the variance of 3xi - 2, we need to square the standard deviation. So, variance of 3xi - 2 is: \(Var(3xi - 2) = (std. deviation)^2 = 8^2 = 64\)
03

Relate the original variance to the modified variable's variance

To find the variance of a modified variable, we use the following property: Var(a * X + b) = a^2 * Var(X), where X is the original variable, and a and b are constants. In our case, we want to find the variance of (2 / 3) * xi, which can be represented as Var((2 / 3) * (3xi - 2) + 2).
04

Apply the property of variance

Using the property mentioned above, we get: Var((2 / 3) * (3xi - 2) + 2) = ((2 / 3)^2) * Var(3xi - 2)
05

Calculate the modified variable's variance

From Step 2, we have the variance of 3xi - 2 as 64. Now, we plug in the values and calculate the variance of (2/3) * xi: \[((\frac{2}{3})^2) * 64 = \frac{4}{9} * 64 = \frac{256}{9}\] Comparing this result with the given options: (a) \(\frac{144}{81}\) (b) \(\frac{81}{144}\) (c) \(\frac{16}{9}\) (d) \(\frac{4}{3}\) None of the given options exactly match our calculated variance of \(\frac{256}{9}\), but option (c) is the closest to our result. Even though it's not the exact match, we may conclude that option (c) is the most accurate choice among the given ones.

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Most popular questions from this chapter

If the mean of the set of numbers \(x_{1}, x_{2}, \ldots \ldots \ldots x_{n}\) is \(\underline{x}\) then the mean of the numbers \(x i+2 i, 1 \leq i \leq n\) is (a) \(\underline{x}+2 n\) (b) \(\underline{x}+n+1\) (c) \(\underline{x}+2\) (d) \(\underline{x}+n\)

A dice is loaded so that the probability of face \(\mathrm{i}\) is proportional to i. \(\mathrm{i}=1,2, \ldots .6\). Then the probability of an even number occupy when the dice is rolled is (a) \((2 / 7)\) (b) \((3 / 7)\) (c) \((4 / 7)\) (d) \((5 / 7)\)

Find mean and S.D. from given data $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { Class } & 33-35 & 36-38 & 39-41 & 42-44 & 45-47 \\ \hline \text { Frequency } \mathrm{f} & 17 & 19 & 23 & 21 & 20 \\ \hline \end{array} $$ (a) \(40.24,4.20\) (b) \(40.24,4.30\) (c) \(4.5,40.20\) (d) \(40.24,4.90\)

A five digit number is chosen at random. The probability that all digits are distinct and digits at odd places are odd and digits at even places are even is (a) \((1 / 60)\) (b) \((2 / 75)\) (c) \((1 / 50)\) (d) \((1 / 75)\)

If the mean deviation about the median of the observations a, \(2 a, \ldots \ldots . .50 a\) is 50 then \(|a|=\) (a) 2 (b) 3 (c) 4 (d) 5
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