If \(4 \sin ^{-1} x+3 \cos ^{-1} x=2 \pi\), then \(x=\) (a) 1 (b) \(-1\) (c) \((1 / 2)\) (d) \(-(1 / 2)\)

Short Answer

Expert verified
\(x=1\) (Option (a)).

Step by step solution

01

Test option (a) - 1

Plug in \(x=1\) into the given equation: \[4 \sin ^{-1}(1) + 3 \cos ^{-1}(1) = 2 \pi\] We know that \(\sin^{-1}(1)=\frac{\pi}{2}\) and \(\cos^{-1}(1)=0\). So the equation becomes: \[4 \left(\frac{\pi}{2}\right) + 3 (0) = 2 \pi\] Simplifying this equation gives: \[2\pi = 2\pi\] The equation holds true, so the answer is: \(x=1\) (Option (a)).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free