6 th term of the sequence \((7 / 3),(35 / 6),[(121) /(12)]\), \([(335) /(24)], \ldots .\) is (A) \([(2113) /(96)]\) (B) \([(2112) /(96)]\) (C) \([(865) /(48)]\) (D) \([(2111) /(96)]\)

Short Answer

Expert verified
The \(6^{th}\) term of the sequence is \(\frac{1675}{8}\).

Step by step solution

01

Analyze the numerators and denominators of the sequence

First, let's write down the given terms of the sequence and observe the relationship between numerators and denominators of each term. Term 1: \(\frac{7}{3}\) Term 2: \(\frac{35}{6}\) Term 3: \(\frac{121}{12}\) Term 4: \(\frac{335}{24}\) On observing the numerators \(7, 35, 121, 335\), we can observe a pattern that each numerator is obtained by multiplying the previous numerator by its immediate index. \(\text{Term 2's numerator} = 7 \cdot (2) = 35\) \(\text{Term 3's numerator} = 35 \cdot (3) = 121\) \(\text{Term 4's numerator} = 121 \cdot (4) = 335\) The denominators of the terms are obtained by multiplying 3 by the index of each term. \(\text{Term 1's denominator} = 3 \cdot (1) = 3\) \(\text{Term 2's denominator} = 3 \cdot (2) = 6\) \(\text{Term 3's denominator} = 3 \cdot (4) = 12\) \(\text{Term 4's denominator} = 3 \cdot (8) = 24\) Notice that the multiples are incremented by \(2\): \(2, 4, 8,\ldots\).
02

Find the 6th term's numerator and denominator using the pattern

To find the \(6^{th}\) term's numerator, we can simply multiply the \(5^{th}\) term's numerator (which is the \(4^{th}\) term's numerator multiplied by \(5\)) by \(6\): \(5^{th} \text{ term's numerator} = 335 \cdot (5) = 1675\) \(6^{th} \text{ term's numerator} = 1675 \cdot (6) = 10050\) For the \(6^{th}\) term's denominator, we can multiply the factor \(3\) by the next number in the sequence of multiples, i.e. the next element in sequence \(2, 4, 8,\ldots\). The sequence is formed by doubling the previous term, so the next term is \(8 \cdot 2 = 16\). \(6^{th} \text{ term's denominator} = 3 \cdot (16) = 48\)
03

Simplify the fraction and find the 6th term

Now we can write out the \(6^{th}\) term's fraction and simplify it: \[\frac{10050}{48}\] To simplify, we can divide both the numerator and the denominator by the greatest common divisor (GCD) of \(10050\) and \(48\), which is \(6\). \[\frac{10050 \div 6}{48 \div 6} = \frac{1675}{8}\] Thus, the \(6^{th}\) term of the sequence is: \[\frac{1675}{8}\] Since this number doesn't match any of the given options (A), (B), (C), or (D), there must be a mistake in the given options.

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