Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 109

Which of the following numerical value have significant figure \(4 ?\) (a) \(1.011\) (b) \(0.010\) (c) \(0.001\) (d) \(0.100\)

Short Answer

Expert verified
Option A: 1.011 contains the significant figure 4.

Step by step solution

01

Option A

Here, in 1.011, we have 4 digits with no leading, sandwiched, or trailing zeros. All the digits are non-zero and therefore significant. We can clearly see that one of the significant digits is 4.
02

Option B

In 0.010, there are 3 digits, with 2 leading zeros and a non-zero digit in the end. According to the rules, leading zeros are never significant, so we only look at the last digit, which is not 4. So, option B is not the correct answer.
03

Option C

In 0.001, there are 3 digits with 2 leading zeros and a non-zero digit in the end. According to the rules, leading zeros are never significant, so 0.001 has only one significant digit, which is not 4. Option C is not the correct answer.
04

Option D

In 0.100, there are 3 digits with one leading zero and two non-zero digits (with a trailing zero). According to the rules, leading zeros are never significant, but trailing zeros in a number with a decimal point are considered significant. So, 0.100 has two significant digits, 1 and 0, which includes no 4. Therefore, option D is not the correct answer. After analyzing all the options, we find that the correct answer is:
05

Answer

Option A: 1.011 contains the significant figure 4.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Dimensional formula for thermal conductivity (k) is.. (a) \(\mathrm{M}^{2} \mathrm{~L}^{1} \mathrm{~T}^{-2} \mathrm{~K}^{-1}\) (b) \(\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2} \mathrm{~K}^{1}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-3} \mathrm{~K}^{-1}\) (d) \(\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-3} \mathrm{~K}^{-1}\)

Kinetic energy \(\mathrm{K}\) and linear momentum \(\mathrm{P}\) are related as \(\mathrm{K}=\left(\mathrm{P}^{2} / 2 \mathrm{~m}\right) .\) What is the equation of the relative error \(\Delta \mathrm{k} / \mathrm{k}\) in measurement of the \(\mathrm{K} ?\) (mass in constant) (a) \((\mathrm{P} / \Delta \mathrm{P})\) (b) \(2(\Delta \mathrm{P} / \mathrm{P})\) (c) \((\mathrm{P} / 2 \Delta \mathrm{P})\) (d) \(4(\Delta \mathrm{P} / \mathrm{P})\)

Pressure \(P=\left(a t^{2} / b x\right)\) where \(x=\) distance, \(t=\) time find the dimensional formula for \(\mathrm{a} / \mathrm{b}\) (a) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-4}\) (b) \(\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-1}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\) (d) \(\mathrm{M}^{+1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\)

For measurement of astronomical distance ............. is used. (a) vernier callipers (b) spherometer (c) screw gauge (d) indirect method

Dimensional formula for power is (a) \(\mathrm{M}^{2} \mathrm{~L}^{-2} \mathrm{~T}^{-3}\) (b) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-2}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{3} \mathrm{~T}^{-1}\) (d) \(\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}\)
See all solutions

Recommended explanations on English Textbooks

Text Comparison

Read Explanation

Linguistic Terms

Read Explanation

Listening and Speaking

Read Explanation

Email

Read Explanation

Language and Social Groups

Read Explanation

Lexis and Semantics Summary

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free