Which physical quantity is represented by $\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{3} \mathrm{~A}^{2}$ ? (a) Resistivity (b) Resistance (c) conductance (d) conductivity

Short Answer

Expert verified
The correct physical quantity represented by \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\) is (d) Conductivity.

Step by step solution

01

Write down the dimensions of each option

(a) Resistivity (\(ρ\)): \(\mathrm{M}\mathrm{L}^{3}\mathrm{T}^{-3}\mathrm{A}^{-2}\) (b) Resistance (\(R\)): \(\mathrm{M}\mathrm{L}^{2}\mathrm{T}^{-3}\mathrm{A}^{-2}\) (c) Conductance (\(G\)): \(\mathrm{M}^{-1}\mathrm{L}^{-2}\mathrm{T}^{3}\mathrm{A}^{2}\) (d) Conductivity (\(σ\)): \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\)
02

Compare given dimensions with the dimensions of each option

Now we need to compare the dimensions given in the exercise, \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\), with the dimensions of the options we wrote down in step 1: For resistivity, \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\) ≠ \(\mathrm{M}\mathrm{L}^{3}\mathrm{T}^{-3}\mathrm{A}^{-2}\) For resistance, \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\) ≠ \(\mathrm{M}\mathrm{L}^{2}\mathrm{T}^{-3}\mathrm{A}^{-2}\) For conductance, \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\) ≠ \(\mathrm{M}^{-1}\mathrm{L}^{-2}\mathrm{T}^{3}\mathrm{A}^{2}\) For conductivity, \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\) = \(\mathrm{M}^{-1}\mathrm{L}^{-3}\mathrm{T}^{3}\mathrm{A}^{2}\)
03

Identify the correct physical quantity

Since the given dimensions match the dimensions of conductivity, the correct answer is: (d) Conductivity

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