Write the dimensional formula of r.m.s (root mean square) speed. (a) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-2}\) (b) \(\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}\) (c) \(\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\) (d) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-1}\)

Short Answer

Expert verified
(c) \(\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\)

Step by step solution

01

We are given the formula for the rms speed: \[v_{rms} = \sqrt{\frac{3k_BT}{m}}\] where \(v_{rms}\) represents the rms speed, \(k_B\) represents the Boltzmann constant, \(T\) represents the temperature, and \(m\) represents the mass of a single gas particle. #Step 2: Analyze the dimensions of each variable in the formula#

Let's find the dimensional formula for each variable in the rms speed formula: \(v_{rms}\) is a speed and therefore has dimensions of length per time: \(\mathrm{L}^{1}\mathrm{T}^{-1}\) \(k_B\) is the Boltzmann constant with dimensions of energy per temperature: \(\mathrm{M}^{1}\mathrm{L}^{2}\mathrm{T}^{-2}\mathrm{K}^{-1}\) \(T\) has dimensions of temperature: \(\mathrm{K}^{1}\) \(m\) has dimensions of mass: \(\mathrm{M}^{1}\) #Step 3: Substituting the dimensions into the formula#
02

We'll now substitute the dimensions of each variable in the formula: \(v_{rms} = \sqrt{\frac{3k_BT}{m}}\) \(\mathrm{L}^{1}\mathrm{T}^{-1} = \sqrt{\frac{\mathrm{M}^{0}\mathrm{L}^{0}\mathrm{T}^{0}(\mathrm{M}^{1}\mathrm{L}^{2}\mathrm{T}^{-2}\mathrm{K}^{-1})(\mathrm{K}^{1})}{\mathrm{M}^{1}}}\) #Step 4: Simplify and find the dimensional formula of rms speed#

Now we simplify the dimensions in the formula and find the dimensional formula for \(v_{rms}\): \(\mathrm{L}^{1}\mathrm{T}^{-1} = \sqrt{\frac{\mathrm{M}^{0}\mathrm{L}^{2}\mathrm{T}^{-2}}{\mathrm{M}^{1}}}\) \(\mathrm{L}^{1}\mathrm{T}^{-1} = \mathrm{M}^{0}\mathrm{L}^{1}\mathrm{T}^{-1}\) From this simplification, we see that the dimensional formula for rms speed is: \(\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\) So, the correct answer is: (c) \(\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free