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Chapter 1: Problem 30

\(\ldots \ldots \ldots \ldots \ldots\) and \(\ldots \ldots \ldots \ldots .\) law's are called inverse square law (a) Gravitation and weak (b) Gravitation and coulomb's (c) Coulomb's and strong (d) Electromagnetic and coulomb's

Short Answer

Expert verified
The correct answer is (b) Gravitation and Coulomb's laws, as both of these follow inverse square laws, where the force between objects is inversely proportional to the square of the distance between them.

Step by step solution

01

Defining Inverse Square Law

An inverse square law states that a specified physical quantity is inversely proportional to the square of the distance between the source and the affected object. Mathematically, its basic equation is given by: \[F = \frac{k}{d^2}\] Where F is the force, k is a constant, and d is the distance between the objects.
02

Analyzing options

Let's breakdown each provided option: (a) Gravitation and weak: Gravitation follows an inverse square law, but the weak nuclear force does not follow an inverse square law as it operates at very short distances within the nucleus of an atom. (b) Gravitation and Coulomb's: Both gravitation and Coulomb's laws follow inverse square laws, where the force between objects is inversely proportional to the square of the distance between them. (c) Coulomb's and strong: Coulomb's law follows an inverse square law, but the strong nuclear force does not follow an inverse square law as it operates at very short distances within the nucleus of an atom. (d) Electromagnetic and Coulomb's: Electromagnetic force is also described by Coulomb's law for electric charges, and the two terms have the same meaning in this context. So, this option is essentially only one force (Coulomb's) that is an inverse square law.
03

Identifying the correct pair

From the above analysis, we can conclude that (b) Gravitation and Coulomb's laws are the correct pair called inverse square laws. So, the correct answer is (b) Gravitation and Coulomb's laws.

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Most popular questions from this chapter

The resistance of two resistance wires are \(R_{1}=(100 \pm 5) \Omega\) and \(\mathrm{R}_{2}=(200 \pm 7) \Omega\) are connected in series. find the maximum absolute error in the equivalent resistance of the combination. (a) \(35 \Omega\) (b) \(12 \Omega\) (c) \(4 \Omega\) (d) \(9 \Omega\)

Match column - I with column - II $$ \begin{array}{|l|l|} \hline \multicolumn{1}{|c|} {\text { Column - I }} & \multicolumn{1}{|c|} {\text { Column - II }} \\ \hline \text { (1) capacitance } & \text { (a) } \mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-3} \mathrm{~A}^{-1} \\ \hline \text { (2) Electricfield } & \text { (b) } \mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-1} \\ \hline \text { (3) planck's constant } & \text { (c) } \mathrm{M}^{-1} \mathrm{~L}^{-2} \mathrm{~T}^{4} \mathrm{~A}^{2} \\ \hline \text { (4) Angular momentum } & \text { (d) } \mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-1} \\ \hline \end{array} $$ (a) \(a, c, b, d\) (b) \(c, a, d, b\) (c) \(c, a, b, d\) (d) \(a, b, d, c\)

\(1 \mathrm{~g}=\ldots \ldots \ldots \ldots \ldots\) amu (a) \(6.02 \times 10^{23}\) (b) \(6.02 \times 10^{-23}\) (c) \(1.66 \times 10^{-27}\) (d) \(1.66 \times 10^{27}\)

Dimensional formula of \(\mathrm{CV}\) ? where C - capacitance and \(\mathrm{V}\) - potential difference (a) \(\mathrm{M}^{1} \mathrm{~L}^{-2} \mathrm{~T}^{4} \mathrm{~A}^{2}\) (b) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-3} \mathrm{~A}^{1}\) (c) \(\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{1} \mathrm{~A}^{-1}\) (d) \(\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{1} \mathrm{~A}^{1}\)

The dimensional formula of plank's constant is ........... (a) \(\mathrm{M}^{3} \mathrm{~L}^{2} \mathrm{~T}^{-1}\) (b) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-1}\) (c) \(\mathrm{M}^{2} \mathrm{~L}^{1} \mathrm{~T}^{-1}\) (d) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-3}\)
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