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Chapter 1: Problem 34

How much times is the strong nuclear force stronger then electro magnetic force ? (a) \(10^{13}\) (b) \(10^{2}\) (c) \(10^{-13}\) (d) \(10^{-2}\)

Short Answer

Expert verified
The strong nuclear force is approximately \(10^2\) times stronger than the electromagnetic force.

Step by step solution

01

Understanding the forces

There are two fundamental forces involved in this problem: the strong nuclear force and the electromagnetic force. The strong nuclear force is responsible for binding protons and neutrons together in the nucleus of an atom. It is the strongest of the four fundamental forces in nature, but it only acts at very short distances (around the size of an atomic nucleus). The electromagnetic force is responsible for the interactions between charged particles (like the repulsion between two electrons or the attraction between an electron and a proton). It is weaker than the strong nuclear force but has an infinite range.
02

Comparing the strengths of the forces

The strong nuclear force is about 100 times stronger than the electromagnetic force, so it can be written as: Strong nuclear force ≈ \(10^2\) x Electromagnetic force
03

Finding the answer

Now that we know the strong nuclear force is approximately \(10^2\) times stronger than the electromagnetic force, we can compare this result to the given options: (a) \(10^{13}\) (b) \(10^{2}\) (c) \(10^{-13}\) (d) \(10^{-2}\) Since we found that the strong nuclear force is approximately \(10^2\) times stronger than the electromagnetic force, the correct answer is: (b) \(10^{2}\)

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Most popular questions from this chapter

If \(\mathrm{A}=3.331 \mathrm{~cm} \mathrm{~B}=3.3 \mathrm{~cm}\) then with regard to significant figure \(\mathrm{A}+\mathrm{B}=\ldots \ldots\) (a) \(6.6 \mathrm{~cm}\) (b) \(6.31 \mathrm{~cm}\) (c) \(6.631 \mathrm{~cm}\) (d) \(6 \mathrm{~cm}\)

Dimensional formula of latent heat is ........ (a) \(\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}\) (b) \(\mathrm{M}^{2} \mathrm{~L}^{0} \mathrm{~T}^{-2}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-1}\) (d) \(\mathrm{M}^{2} \mathrm{~L}^{2} \mathrm{~T}^{-1}\)

The radius of circle is \(1.26 \mathrm{~cm}\). According to the concept of significant figures area of it can be represented as - (a) \(4.9850 \mathrm{~cm}^{2}\) (b) \(4.985 \mathrm{~cm}^{2}\) (c) \(4.98 \mathrm{~cm}^{2}\) (d) \(9.98 \mathrm{~cm}^{2}\)

\(F=A_{0}\left(1-e^{-(B x t) 2}\right)\) where \(F\) is force and \(x\) is displacement. write the dimension formula of \(B\) (a) \(\mathrm{M}^{2} \mathrm{~L}^{1} \mathrm{~T}^{-1}\) (b) \(\mathrm{M}^{0} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\) (d) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-1}\)

The intercepted area of the spherical surface about the center is $0.025 \mathrm{~m}^{2}\( having diameter \)50 \mathrm{~cm}$ what will be solid angle? (a) \(4 \times 10^{-1} \mathrm{sr}\) (b) \(1 \times 10^{3} \mathrm{sr}\) (c) \(10^{-1} \mathrm{sr}\) (d) \(5 \times 10^{-1} \mathrm{sr}\)
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