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Chapter 1: Problem 34

How much times is the strong nuclear force stronger then electro magnetic force ? (a) \(10^{13}\) (b) \(10^{2}\) (c) \(10^{-13}\) (d) \(10^{-2}\)

Short Answer

Expert verified
The strong nuclear force is approximately \(10^2\) times stronger than the electromagnetic force.

Step by step solution

01

Understanding the forces

There are two fundamental forces involved in this problem: the strong nuclear force and the electromagnetic force. The strong nuclear force is responsible for binding protons and neutrons together in the nucleus of an atom. It is the strongest of the four fundamental forces in nature, but it only acts at very short distances (around the size of an atomic nucleus). The electromagnetic force is responsible for the interactions between charged particles (like the repulsion between two electrons or the attraction between an electron and a proton). It is weaker than the strong nuclear force but has an infinite range.
02

Comparing the strengths of the forces

The strong nuclear force is about 100 times stronger than the electromagnetic force, so it can be written as: Strong nuclear force ≈ \(10^2\) x Electromagnetic force
03

Finding the answer

Now that we know the strong nuclear force is approximately \(10^2\) times stronger than the electromagnetic force, we can compare this result to the given options: (a) \(10^{13}\) (b) \(10^{2}\) (c) \(10^{-13}\) (d) \(10^{-2}\) Since we found that the strong nuclear force is approximately \(10^2\) times stronger than the electromagnetic force, the correct answer is: (b) \(10^{2}\)

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Most popular questions from this chapter

If the length of rod \(\mathrm{A}\) is \((2.35 \pm 0.01) \mathrm{cm}\) and that of \(\mathrm{B}\) is \((5.68 \pm 0.01) \mathrm{cm}\) then the rod \(\mathrm{B}\) is longer than \(\mathrm{rod} \mathrm{A}\) by \(\ldots\) (a) \((2.43 \pm 0.00) \mathrm{cm}\) (b) \((3.33 \pm 0.02) \mathrm{cm}\) (c) \((2.43 \pm 0.01) \mathrm{cm}\) (d) \((2.43 \pm 0.001) \mathrm{cm}\)

If $\mathrm{P}=\left[\left(\mathrm{A}^{2} \mathrm{~B}\right) /\left(\mathrm{C}^{3}\right)\right]\( where percentage error in \)\mathrm{A}, \mathrm{B}\( and \)\mathrm{C}$ are respectively \(\pm 2 \% \pm 3 \%\) and \(\pm 5 \%\) then total percentage error in measurement of \(\mathrm{p}\) (a) \(18 \%\) (b) \(14 \%\) (c) \(21 \%\) (d) \(12 \%\)

The percentage error in the distance \(100 \pm 5 \mathrm{~cm}\) is ... (a) \(5 \%\) (b) \(6 \%\) (c) \(8 \%\) (d) \(20 \%\)

Write dimensional formula of coefficient of viscosity (a) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-1}\) (b) \(\mathrm{M}^{-1} \mathrm{~L}^{1} \mathrm{~T}^{1}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{-1} \mathrm{~T}^{-1}\) (d) \(\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-1}\)

In an experiment to determine the density of a cube the percentage error in the measurement of mass is \(0.25 \%\) and the percentage error in the measurement of length is \(0.50 \%\) what will be the percentage error in the determination of its density? (a) \(2.75 \%\) (b) \(1.75 \%\) (c) \(0.75 \%\) (d) \(1.25 \%\)
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