\([(1\) femtometer \() /(100\) nanometer \()]=\ldots \ldots \ldots \ldots \ldots\) (a) \(10^{-6}\) (b) \(10^{-8}\) (c) \(10^{24}\) (d) \(10^{-24}\)

Short Answer

Expert verified
The short answer is: \[(b) \: 10^{-8}\]

Step by step solution

01

Understanding the prefixes

A femtometer is \(10^{-15}\) meters and a nanometer is \(10^{-9}\) meters. We need to convert the given lengths into meters using these prefixes.
02

Converting lengths to meters

Convert 1 femtometer to meters by multiplying by the conversion factor for femtometers: \[1 \text{ femtometer} = 1 \times 10^{-15} \text{ meters}\] Convert 100 nanometers to meters by multiplying by the conversion factor for nanometers: \[100 \text{ nanometers} = 100 \times 10^{-9} \text{ meters}\]
03

Divide the lengths to find the ratio

Divide 1 femtometer by 100 nanometers to find the ratio: \[\frac{1 \times 10^{-15} \text{ meters}}{100 \times 10^{-9} \text{ meters}}\]
04

Simplify the expression

Simplify the expression by dividing the numbers and combining the powers of 10: \[\frac{1 \times 10^{-15}}{100 \times 10^{-9}} = \frac{1}{100} \times \frac{10^{-15}}{10^{-9}} = \frac{1}{100} \times 10^{(-15-(-9))} = \frac{1}{100} \times 10^{-6}\]
05

Convert the fraction to a power of 10

Convert the fraction \(\frac{1}{100}\) to a power of 10 by changing 100 to \(10^2\): \[\frac{1}{10^2} \times 10^{-6} = 10^{-2} \times 10^{-6}\]
06

Combine powers of 10

Combine the powers of 10 to get the final answer: \[10^{-2} \times 10^{-6} = 10^{(-2-6)} = 10^{-8}\]
07

Match the answer to one of the given choices

Our final answer is \(10^{-8}\) which matches choice (b). Therefore, the correct answer is: \[(b) \: 10^{-8}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free