Chapter 1: Problem 75
Unit of momentum physical quantity? (a) newton - second (b) newton/second (c) Joule (d) Joule/second
Chapter 1: Problem 75
Unit of momentum physical quantity? (a) newton - second (b) newton/second (c) Joule (d) Joule/second
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Get started for freePressure \(P=\left(a t^{2} / b x\right)\) where \(x=\) distance, \(t=\) time find the dimensional formula for \(\mathrm{a} / \mathrm{b}\) (a) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-4}\) (b) \(\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-1}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\) (d) \(\mathrm{M}^{+1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\)
For measurement of astronomical distance ............. is used. (a) vernier callipers (b) spherometer (c) screw gauge (d) indirect method
Dimensional formula for torque is (a) \(\mathrm{M}^{2} \mathrm{~L}^{2} \mathrm{~T}^{-3}\) (b) \(\mathrm{M}^{2} \mathrm{~L}^{1} \mathrm{~T}^{-2}\) (c) \(\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}\) (d) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-2}\)
\(1 \mathrm{~g}=\ldots \ldots \ldots \ldots \ldots\) amu (a) \(6.02 \times 10^{23}\) (b) \(6.02 \times 10^{-23}\) (c) \(1.66 \times 10^{-27}\) (d) \(1.66 \times 10^{27}\)
The force \(F\) is represented by equation \(F=P \ell+Q \ell^{-1}\), where \(\ell\) is the length. The unit of \(P\) is same as that of $\ldots \ldots \ldots \ldots \ldots$ (a) Surface tension (b) velocity (c) force (d) momentum
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