For the following questions, statement as well as the reason(s) are given. Each questions has four options. Select the correct option. (a) Statement \(-1\) is true, statement \(-2\) is true; statement \(-2\) is the correct explanation of statement \(-1\). (b) Statement \(-1\) is true, statement \(-2\) is true but statement \(-2\) is not the correct explanation of statement \(-1\) (c) Statement \(-1\) is true, statement \(-2\) is false (d) Statement \(-1\) is false, statement \(-2\) is true (A) a (B) \(b\) (C) \(\mathrm{c}\) (D) d Statement \(-1:\) For a particle executing S.H.M. with an amplitude of $0.01 \mathrm{~m}\( and frequency \)30 \mathrm{hz}\(, the maximum acceleration is \)36 \pi^{2} \mathrm{~m} / \mathrm{s}^{2}$. Statement \(-2:\) The maximum acceleration for the above particle is $\pm \omega 2 \mathrm{~A}\(, where \)\mathrm{A}$ is amplitude. (A) a (B) \(\mathrm{b}\) (C) \(c\) (D) \(\mathrm{d}\)

Short Answer

Expert verified
The correct answer is (A) Both statement 1 and statement 2 are true, and statement 2 is the correct explanation of statement 1.

Step by step solution

01

Calculate the maximum acceleration for statement 1

Given the amplitude A = 0.01 m and frequency f = 30 Hz, we need to find the maximum acceleration. Since the maximum acceleration is given by the formula: \[a_{max} = \omega^2 A\] where \(\omega = 2\pi f\) is the angular frequency, we can calculate the maximum acceleration using the given values. Step 2: Calculate the angular frequency
02

Calculate the angular frequency

With f = 30 Hz, we can calculate the angular frequency as follows: \[\omega = 2\pi f = 2\pi(30) = 60\pi\ rad/s\] Step 3: Calculate the maximum acceleration
03

Calculate the maximum acceleration using the angular frequency

Now we can calculate the maximum acceleration: \[a_{max} = \omega^2 A = (60\pi)^2 (0.01 \mathrm{m}) = 36\pi^2\ \mathrm{m/s^2}\] Step 4: Analyze statement 2
04

Check the validity of the statement 2

We already calculated the maximum acceleration for the given particle using the formula \(a_{max} = \omega^2 A\). As Statement 2 suggests, this is indeed the correct formula. Therefore, statement 2 is true. Step 5: Comparison of statements and options
05

Compare statements and options

Both statement 1 and statement 2 are true. Additionally, statement 2 is indeed the correct explanation for statement 1. Therefore, the correct option is: (a) Statement 1 is true and statement 2 is true. Statement 2 is the correct explanation of statement 1.

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Most popular questions from this chapter

A small spherical steel ball is placed at a distance slightly away from the center of a concave mirror having radius of curvature \(250 \mathrm{~cm}\). If the ball is released, it will now move on the curved surface. What will be the periodic time of this motion? Ignore frictional force and take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$. (A) \((\pi / 4) \mathrm{s}\) (B) \(\pi \mathrm{s}\) (C) \((\pi / 2) \mathrm{s}\) (D) \(2 \pi \mathrm{s}\)

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For the following questions, statement as well as the reason(s) are given. Each questions has four options. Select the correct option. (a) Statement \(-1\) is true, statement \(-2\) is true; statement \(-2\) is the correct explanation of statement \(-1\). (b) Statement \(-1\) is true, statement \(-2\) is true but statement \(-2\) is not the correct explanation of statement \(-1\). (c) Statement \(-1\) is true, statement \(-2\) is false (d) Statement \(-1\) is false, statement \(-2\) is true (A) a (B) \(\mathrm{b}\) (C) \(c\) (D) \(\mathrm{d}\) Statement \(-1:\) For a particle executing SHM, the amplitude and phase is decided by its initial position and initial velocity. Statement \(-2:\) In a SHM, the amplitude and phase is dependent on the restoring force. (A) a (B) \(b\) (C) \(\mathrm{c}\) (D) \(\mathrm{d}\)

A string of length \(70 \mathrm{~cm}\) is stretched between two rigid supports. The resonant frequency for this string is found to be \(420 \mathrm{~Hz}\) and \(315 \mathrm{~Hz}\). If there are no resonant frequencies between these two values, then what would be the minimum resonant frequency of this string ? (A) \(10.5 \mathrm{~Hz}\) (B) \(1.05 \mathrm{~Hz}\) (C) \(105 \mathrm{~Hz}\) (D) \(1050 \mathrm{~Hz}\)

Two sitar strings \(\mathrm{A}\) and \(\mathrm{B}\) playing the note "Dha" are slightly out of time and produce beats of frequency \(5 \mathrm{~Hz}\). The tension of the string B is slightly increased and the beat frequency is found to decrease to \(3 \mathrm{~Hz}\). What is the original frequency of \(\mathrm{B}\) if the frequency of \(\mathrm{A}\) is \(427 \mathrm{~Hz}\) ? (A) 432 (B) 422 (C) 437 (D) 417

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