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Chapter 10: Problem 1468

When temperature increases, the frequency of a tuning fork (A) Increases (B) Decreases (C) remains same (D) Increases or decreases depending on the material.

Short Answer

Expert verified
The correct answer is (D) Increases or decreases depending on the material, as the frequency change depends on the specific properties of the tuning fork's material.

Step by step solution

01

Recall the relationship between frequency and temperature

When the temperature of a tuning fork changes, its physical properties, such as its dimensions and materials, will also be affected. These changes can cause the frequency of the tuning fork to alter. However, the nature of this alteration (increase, decrease, or remain the same) depends on the material and the specific temperature range.
02

Analyze the options provided

Let's go through each provided option: (A) Increases: This suggests that as the temperature increases, the frequency of the tuning fork will always increase. (B) Decreases: This suggests that as the temperature increases, the frequency of the tuning fork will always decrease. (C) remains the same: This suggests that the frequency is not affected by the changes in temperature. (D) Increases or decreases depending on the material: This option leaves open the possibility that the temperature could have different effects on the frequency depending on the specific material of the tuning fork.
03

Determine the correct answer

We know that temperature can affect the physical properties of the tuning fork, which can lead to changes in its frequency. However, the specific relationship between temperature and frequency changes depends on the material. Thus, the correct answer is (D) Increases or decreases depending on the material.

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Most popular questions from this chapter

A tuning fork of frequency \(480 \mathrm{~Hz}\) produces 10 beats/s when sounded with a vibrating sonometer string. What must have been the frequency of the string if a slight increase in tension produces fewer beats per second than before? (A) \(480 \mathrm{~Hz}\) (B) \(490 \mathrm{~Hz}\) (C) \(460 \mathrm{~Hz}\) (D) \(470 \mathrm{~Hz}\)

Which of the equation given below represents a S.H.M.? (A) acceleration \(=-\mathrm{k}(\mathrm{x}+\mathrm{a})\) (B) acceleration \(=\mathrm{k}(\mathrm{x}+\mathrm{a})\) (C) acceleration \(=\mathrm{kx}\) (D) acceleration \(=-\mathrm{k}_{0} \mathrm{x}+\mathrm{k}_{1} \mathrm{x}^{2}\) \\{Here \(\mathrm{k}, \mathrm{k}_{0}\) and \(\mathrm{k}_{1}\) are force constants and units of \(\mathrm{x}\) and a is meter \(\\}\)

A simple pendulum is executing S.H.M. around point \(\mathrm{O}\) between the end points \(B\) and \(C\) with a periodic time of \(6 \mathrm{~s}\). If the distance between \(\mathrm{B}\) and \(\mathrm{C}\) is \(20 \mathrm{~cm}\) then in what time will the bob move from \(C\) to \(D\) ? Point \(D\) is at the mid-point of \(C\) and \(\mathrm{O}\). (A) \(1 \mathrm{~s}\) (B) \(2 \mathrm{~s}\) (C) \(3 \mathrm{~s}\) (D) \(4 \mathrm{~s}\)

A body of mass \(1 \mathrm{~kg}\) suspended from the free end of a spring having force constant \(400 \mathrm{Nm}^{-1}\) is executing S.H.M. When the total energy of the system is 2 joule, the maximum acceleration is $\ldots \ldots . \mathrm{ms}^{-2}$. (A) \(8 \mathrm{~ms}^{-2}\) (B) \(10 \mathrm{~ms}^{-2}\) (C) \(40 \mathrm{~ms}^{-2}\) (D) \(40 \mathrm{cms}^{-2}\)

For particles \(\mathrm{A}\) and \(\mathrm{B}\) executing S.H.M., the equation for displacement is given by $\mathrm{y}_{1}=0.1 \sin (100 \mathrm{t}+\mathrm{p} / 3)$ and \(\mathrm{y}_{2}=0.1\) cos pt respectively. The phase difference between velocity of particle \(\mathrm{A}\) with respect to that of \(\mathrm{B}\) is \(\ldots \ldots\) \((\mathrm{A})-(\pi / 3)\) (B) \((\pi / 6)\) (C) \(-(\pi / 6)\) (D) \((\pi / 3)\)
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