Chapter 10: Problem 1487
Which of the following changes at an antinode in a stationary wave? (A) Density only (B) Pressure only (C) Both pressure and density (D) Neither pressure nor density
Chapter 10: Problem 1487
Which of the following changes at an antinode in a stationary wave? (A) Density only (B) Pressure only (C) Both pressure and density (D) Neither pressure nor density
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Get started for freeThe displacement of a S.H.O. is given by the equation \(\mathrm{x}=\mathrm{A}\) \(\cos \\{\omega t+(\pi / 8)\\}\). At what time will it attain maximum velocity? (A) \((3 \pi / 8 \omega)\) (B) \((8 \pi / 3 \omega)\) (C) \((3 \pi / 16 \omega)\) (D) \((\pi / 16 \pi)\).
A wave \(\mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t}-\mathrm{kx})\) on a string meets with another wave producing a node at \(\mathrm{x}=0 .\) Then the equation of the unknown wave is \(\ldots \ldots \ldots\) (A) \(y=a \sin (\omega t+k x)\) (B) \(\mathrm{y}=-\mathrm{a} \sin (\omega \mathrm{t}+\mathrm{kx})\) (C) \(\mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t}-\mathrm{kx})\) (D) \(\mathrm{y}=-\mathrm{a} \sin (\omega \mathrm{t}-\mathrm{kx})\)
For a particle executing \(\mathrm{S} . \mathrm{H} \mathrm{M} .\), when the potential energy of the oscillator becomes \(1 / 8\) the maximum potential energy, the displacement of the oscillator in terms of amplitude A will be........... (A) \((\mathrm{A} / \sqrt{2})\) (B) \(\\{\mathrm{A} /(2 \sqrt{2})\\}\) (C) \((\mathrm{A} / 2)\) (D) \(\\{\mathrm{A} /(3 \sqrt{2})\\}\)
The equation for displacement of a particle at time \(t\) is given by the equation \(\mathrm{y}=3 \cos 2 \mathrm{t}+4 \sin 2 \mathrm{t}\). The frequency of the particle is \(\ldots \ldots \mathrm{s}^{-1}\). (A) \((1 / \pi)\) (B) \(\pi\) (C) \((1 / 2 \pi)\) (D) \((\pi / 2)\)
If two SHM's are given by the equation $\mathrm{y}_{1}=0.1 \sin [\pi \mathrm{t}+(\pi / 3)]\( and \)\mathrm{y}_{2}=0.1 \cos \pi \mathrm{t}$, then the phase difference between the velocity of particle 1 and 2 is \(\ldots \ldots \ldots\) (A) \(\pi / 6\) (B) \(-\pi / 3\) (C) \(\pi / 3\) (D) \(-\pi / 6\)
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