Chapter 10: Problem 1499
The length of a string tied across two rigid supports is \(40 \mathrm{~cm}\). The maximum wavelength of a stationary wave that can be produced in it is \(\ldots \ldots \ldots \mathrm{cm}\). (A) 20 (B) 40 (C) 80 (D) 120
Chapter 10: Problem 1499
The length of a string tied across two rigid supports is \(40 \mathrm{~cm}\). The maximum wavelength of a stationary wave that can be produced in it is \(\ldots \ldots \ldots \mathrm{cm}\). (A) 20 (B) 40 (C) 80 (D) 120
All the tools & learning materials you need for study success - in one app.
Get started for freeThe speed of a particle executing motion changes with time according to the equation $\mathrm{y}=\mathrm{a} \sin \omega \mathrm{t}+\mathrm{b} \cos \omega \mathrm{t}\(, then \)\ldots \ldots \ldots$ (A) Motion is periodic but not a S.H.M. (B) It is a S.H.M. with amplitude equal to \(\mathrm{a}+\mathrm{b}\) (C) It is a S.H.M. with amplitude equal to \(\mathrm{a}^{2}+\mathrm{b}^{2}\)
A rocket is moving at a speed of \(130 \mathrm{~m} / \mathrm{s}\) towards a stationary target. While moving, it emits a wave of frequency $800 \mathrm{~Hz}$. Calculate the frequency of the sound as detected by the target. (Speed of wave \(=330 \mathrm{~m} / \mathrm{s}\) ) (A) \(1320 \mathrm{~Hz}\) (B) \(2540 \mathrm{~Hz}\) (C) \(1270 \mathrm{~Hz}\) (D) \(660 \mathrm{~Hz}\)
A string of linear density \(0.2 \mathrm{~kg} / \mathrm{m}\) is stretched with a force of \(500 \mathrm{~N}\). A transverse wave of length \(4.0 \mathrm{~m}\) and amplitude \(1 / 1\) meter is travelling along the string. The speed of the wave is \(\ldots \ldots \ldots \ldots \mathrm{m} / \mathrm{s}\) (A) 50 (B) \(62.5\) (C) 2500 (D) \(12.5\)
A particle having mass \(1 \mathrm{~kg}\) is executing S.H.M. with an amplitude of \(0.01 \mathrm{~m}\) and a frequency of \(60 \mathrm{hz}\). The maximum force acting on this particle is \(\ldots \ldots . . \mathrm{N}\) (A) \(144 \pi^{2}\) (B) \(288 \pi^{2}\) (C) \(188 \pi^{2}\) (D) None of these. (A) \(x=a \sin 2 p \sqrt{(\ell / g) t}\) (B) \(x=a \cos 2 p \sqrt{(g / \ell) t}\) (C) \(\mathrm{x}=\mathrm{a} \sin \sqrt{(\mathrm{g} / \ell) \mathrm{t}}\) (D) \(\mathrm{x}=\mathrm{a} \cos \sqrt{(\mathrm{g} / \ell) \mathrm{t}}\)
Equation for a progressive harmonic wave is given by $\mathrm{y}=8 \sin 2 \pi(0.1 \mathrm{x}-2 \mathrm{t})\(, where \)\mathrm{x}\( and \)\mathrm{y}$ are in \(\mathrm{cm}\) and \(\mathrm{t}\) is in seconds. What will be the phase difference between two particles of this wave separated by a distance of \(2 \mathrm{~cm} ?\) (A) \(18^{\circ}\) (B) \(36^{\circ}\) (C) \(72^{\circ}\) (D) \(54^{\circ}\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.