Two identical capacitors have the same capacitance \(\mathrm{C}\). one of them
is charged to a potential \(\mathrm{V}_{1}\) and the other to \(\mathrm{V}_{2}\).
The negative ends of the capacitors are connected together. When the positive
ends are also connected, the decrease in energy of the combined system is
(A) \((1 / 4) \mathrm{C}\left(\mathrm{V}_{1}^{2}-\mathrm{V}_{2}^{2}\right)\)
(B) \((1 / 4) \mathrm{C}\left(\mathrm{V}_{1}^{2}+\mathrm{V}_{2}^{2}\right)\)
(C) \((1 / 4) \mathrm{C}\left(\mathrm{V}_{1}-\mathrm{V}_{2}\right)^{2}\)
(D) \((1 / 4) \mathrm{C}\left(\mathrm{V}_{1}+\mathrm{V}_{2}\right)^{2}\)