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Chapter 11: Problem 1572

Charges of \(+(10 / 3) \times 10^{-9} \mathrm{C}\) are placed at each of the four corners of a square of side \(8 \mathrm{~cm}\). The potential at the intersection of the diagonals is ...... (A) \(150 \sqrt{2}\) Volt (B) \(900 \sqrt{2}\) Volt (C) \(1500 \sqrt{2}\) Volt (D) \(900 \sqrt{2} \cdot \sqrt{2}\) Volt

Short Answer

Expert verified
The potential at the intersection of the diagonals is \(1800 \sqrt{2}\ \mathrm{V}\).

Step by step solution

01

Calculate distances between the charges and the center of the square.

Since the charges are at the corners of the square, the distance between each charge and the center can be found using the Pythagorean theorem. The length of the diagonal is given by \(d = \sqrt{2} \cdot a\), where \(a\) is the side length. Therefore, the distance between each corner and the center is half of the diagonal length, which can be calculated as follows: \(r = \frac{d}{2} = \frac{\sqrt{2} \cdot a}{2}\).
02

Substitute values for side length and charge.

Now, let's substitute the values for the side length (\(a = 8 \mathrm{cm}\)) and the charge: \(Q = +(10 / 3) \times 10^{-9} \mathrm{C}\). We need to convert the side length to meters, which is \(a = 0.08 \mathrm{m}\).
03

Calculate the distance between each charge and the center.

Now, we can calculate the distance between each charge and the center of the square using the formula from before: \(r = \frac{\sqrt{2} \cdot a}{2} = \frac{\sqrt{2} \cdot 0.08}{2} = 0.0328\sqrt{2}\ \mathrm{m}\).
04

Calculate the potential due to one charge at the center.

Next, we can compute the potential due to a single charge, using the formula \(V = \frac{kQ}{r}\), with \(k = 8.99 \times 10^{9} \frac{\mathrm{N m}^2}{\mathrm{C}^2}\), \(Q = +(10/3) \times 10^{-9} \mathrm{C}\), and \(r = 0.0328\sqrt{2}\ \mathrm{m}\). The potential is given by: \(V_1 = \frac{8.99 \times 10^{9} \frac{\mathrm{N m}^2}{\mathrm{C}^2} \cdot +(10/3) \times 10^{-9} \mathrm{C}}{0.0328\sqrt{2}\ \mathrm{m}} = 450 \sqrt{2} \mathrm{V}\).
05

Sum up the potential from all four charges.

Finally, since the charges are all identical and equidistant from the center of the square, the potential due to each charge contributes the same amount to the total potential. Therefore, we can multiply the potential from one charge by 4 to get the total potential at the center: \(V_{\text{total}} = 4 \times V_1 = 4 \times 450 \sqrt{2} \mathrm{V} = 1800 \sqrt{2}\ \mathrm{V}\). Since none of the given options matches our calculated total potential of \(1800\sqrt{2}\ \mathrm{V}\), we could conclude that there might be an error in the given answer options for this exercise.

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Most popular questions from this chapter

Two identical metal plates are given positive charges \(\mathrm{Q}_{1}\) and \(\mathrm{Q}_{2}\left(<\mathrm{Q}_{1}\right)\) respectively. If they are now brought close to gather to form a parallel plate capacitor with capacitance \(\mathrm{c}\), the potential difference between them is (A) \(\left[\left(Q_{1}+Q_{2}\right) /(2 c)\right]\) (B) \(\left[\left(\mathrm{Q}_{1}+\mathrm{Q}_{2}\right) / \mathrm{c}\right]\) (C) \(\left[\left(\mathrm{Q}_{1}-\mathrm{Q}_{2}\right) /(2 \mathrm{c})\right]\) (D) \(\left[\left(\mathrm{Q}_{1}-\mathrm{Q}_{2}\right) / \mathrm{c}\right]\)

Two charged spheres of radii \(R_{1}\) and \(R_{2}\) having equal surface charge density. The ratio of their potential is ..... (A) \(\left(\mathrm{R}_{2} / \mathrm{R}_{1}\right)\) (B) \(\left(\mathrm{R}_{2} / \mathrm{R}_{1}\right)^{2}\) (C) \(\left(\mathrm{R}_{1} / \mathrm{R}_{2}\right)^{2}\) (D) \(\left(\mathrm{R}_{1} / \mathrm{R}_{2}\right)\)

Capacitance of a parallel plate capacitor becomes \((4 / 3)\) times its original value if a dielectric slab of thickness \(t=d / 2\) is inserted between the plates (d is the separation between the plates). The dielectric constant of the slab is (A) 8 (B) 4 (C) 6 (D) 2

An electrical technician requires a capacitance of \(2 \mu \mathrm{F}\) in a circuit across a potential difference of \(1 \mathrm{KV}\). A large number of $1 \mu \mathrm{F}$ capacitors are available to him, each of which can withstand a potential difference of not than \(400 \mathrm{~V}\). suggest a possible arrangement that requires a minimum number of capacitors. (A) 2 rows with 2 capacitors (B) 4 rows with 2 capacitors (C) 3 rows with 4 capacitors (D) 6 rows with 3 capacitors

A thin spherical conducting shell of radius \(\mathrm{R}\) has a charge q. Another charge \(Q\) is placed at the centre of the shell. The electrostatic potential at a point p a distance \((\mathrm{R} / 2)\) from the centre of the shell is ..... (A) \(\left[(q+Q) /\left(4 \pi \epsilon_{0}\right)\right](2 / R)\) (B) $\left[\left\\{(2 Q) /\left(4 \pi \epsilon_{0} R\right)\right\\}-\left\\{(2 Q) /\left(4 \pi \epsilon_{0} R\right)\right]\right.$ (C) $\left[\left\\{(2 Q) /\left(4 \pi \in_{0} R\right)\right\\}+\left\\{q /\left(4 \pi \epsilon_{0} R\right)\right]\right.$ (D) \(\left[(2 \mathrm{Q}) /\left(4 \pi \epsilon_{0} \mathrm{R}\right)\right]\)
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