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Chapter 12: Problem 1791

Find the equivalent resistance a cross \(\mathrm{AB}\) (A) \(1 \Omega\) (B) \(2 \Omega\) (C) \(3 \Omega\) (D) \(4 \Omega\)

Short Answer

Expert verified
The given exercise does not provide enough information about the values of the resistors or their connections in the circuit. Please provide a circuit diagram or more information about the circuit components to find the equivalent resistance across AB.

Step by step solution

01

Identify Circuit Connections

First, we need to identify the connections between resistors in the circuit. In this case, there are no clarifications about the components present in the circuit. We will assume there are resistors with equal values, connected either in series or parallel.
02

Series Connection Formula

The total resistance \(R_s\) for resistors connected in series can be calculated using the series connection formula: \[ R_s = R_1 + R_2 + R_3 + ... + R_n \] where \(R_1, R_2, R_3, ..., R_n\) are the values of resistors connected in series.
03

Parallel Connection Formula

The total resistance \(R_p\) for resistors connected in parallel can be calculated using the parallel connection formula: \[ \frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ... + \frac{1}{R_n} \] where \(R_1, R_2, R_3, ..., R_n\) are the values of resistors connected in parallel.
04

Calculate Equivalent Resistance

To find the equivalent resistance across AB, we will use the series and parallel connection formulas as needed for the given circuit configuration. Unfortunately, the given exercise does not provide enough information about the values of the resistors or their connections in the circuit. Please provide a circuit diagram or more information about the circuit components to find the equivalent resistance across AB.

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Most popular questions from this chapter

Two batteries each of emf \(2 \mathrm{~V}\) and internal resistance \(1 \Omega\) are connected in series to a resistor \(R\). Maximum Possible power consumed by the resistor \(=\ldots .\) (A) \(3.2 \mathrm{~W}\) (B) \((16 / 9) \mathrm{W}\) (C) \((8 / 9) \mathrm{W}\) (D) \(2 \mathrm{~W}\)

4 cell each of emf \(2 \mathrm{v}\) and internal resistance of \(1 \Omega\) are connected in parallel to a load resistor of \(2 \Omega\) Then the current through the load resistor is.... (A) \(2 \mathrm{~A}\) (B) \(1.5 \mathrm{~A}\) (C) \(1 \mathrm{~A}\) (D) \(0.888 \mathrm{~A}\)

A bulb of \(300 \mathrm{~W}\) and \(220 \mathrm{~V}\) is connected with a source of \(110 \mathrm{~V}\). What is the \(\%\) decrease in power? (A) \(100 . \%\) (B) \(75 \%\) (C) \(70 \%\) (D) \(25 \%\)

An electric kettle has two coils when one of these is switched on. the water in the kettle boils in 6 minutes. When the other coil is switched on, boils in 3 minutes If the two coils are connected in parallel, the time taken to boil water in the kettle is. (A) 3 minutes (B) 6 minutes (C) 2 minutes (D) 9 minutes

The resistance of the series combination of two resistances is \(\mathrm{S}\), when they are joined in parallel the total resistance is \(\mathrm{P}\) If $S=n P\(, then the minimum possible value of \)n$ is.... (A) 4 (B) 3 (C) 2 (D) 1
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