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Chapter 13: Problem 1879

The direction of mag. field lines close to a straight conductor carrying current will be (a) Along the length of the conductor (b) Radially outward (c) Circular in a plane perpendicular to the conductor (d) Helical

Short Answer

Expert verified
The direction of the magnetic field lines close to a straight conductor carrying current is (c) Circular in a plane perpendicular to the conductor, as determined by the right-hand rule for a straight conductor.

Step by step solution

01

Right-Hand Rule for a Straight Conductor

To find the direction of the magnetic field around a straight conductor carrying current, use the right-hand rule. To apply the rule, put your right thumb in the direction of the current and curl your fingers around the wire. The direction in which your fingers curl is the direction of the magnetic field.
02

Analyze the Given Options

Now, we consider each of the given options and see if they match the result from the right-hand rule. (a) Along the length of the conductor: The right-hand rule indicates that the magnetic field direction is circular around the wire, not along its length. (b) Radially outward: The magnetic field direction from the right-hand rule is circular and not radially outward. (c) Circular in a plane perpendicular to the conductor: This option matches the result obtained from the right-hand rule, where the magnetic field direction is circular around the wire, and the plane of the circles is perpendicular to the conductor. (d) Helical: The magnetic field direction we found using the right-hand rule is not helical.
03

Choose the Correct Option

Based on the analysis of the given options, we conclude that the direction of the magnetic field lines close to a straight conductor carrying current is (c) Circular in a plane perpendicular to the conductor.

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Most popular questions from this chapter

Two thin long parallel wires separated by a distance \(\mathrm{y}\) are carrying a current I Amp each. The magnitude of the force per unit length exerted by one wire on other is (a) \(\left[\left(\mu_{0} I^{2}\right) / y^{2}\right]\) (b) \(\left[\left(\mu_{o} I^{2}\right) /(2 \pi \mathrm{y})\right]\) (c) \(\left[\left(\mu_{0}\right) /(2 \pi)\right](1 / y)\) (d) $\left[\left(\mu_{0}\right) /(2 \pi)\right]\left(1 / \mathrm{y}^{2}\right)$

A conducting circular loop of radius a carries a constant current I. It is placed in a uniform magnetic field \(\mathrm{B}^{-}\), such that \(\mathrm{B}^{-}\) is perpendicular to the plane of the Loop. The magnetic force acting on the Loop is (a) \(\mathrm{B}^{-} \operatorname{Ir}\) (b) \(\mathrm{B}^{-} \mathrm{I} \pi \mathrm{r}^{2}\) (c) Zero (d) BI \((2 \pi \mathrm{r})\)

When 2 Amp current is passed through a tangent galvanometer. It gives a deflection of \(30^{\circ} .\) For \(60^{\circ}\) deflection, the current must be (a) \(1 \mathrm{Amp}\) (b) \(2 \sqrt{3 a m p}\) (c) \(4 \mathrm{amp}\) (d) \(6 \mathrm{Amp}\)

The mag. field due to a current carrying circular Loop of radius $3 \mathrm{~cm}\( at a point on the axis at a distance of \)4 \mathrm{~cm}$ from the centre is \(54 \mu \mathrm{T}\) what will be its value at the centre of the LOOP. (a) \(250 \mu \mathrm{T}\) (b) \(150 \mu \mathrm{T}\) (c) \(125 \mu \mathrm{T}\) (d) \(75 \mu \mathrm{T}\)

Force between two identical bar magnets whose centers are I meter apart is \(4.8 \mathrm{~N}\), when their axes are in the same line. If separation is increased to \(2 r\), the force between them is reduced to (a) \(2.4 \mathrm{~N}\) (b) \(1.2 \mathrm{~N}\) (c) \(0.6 \mathrm{~N}\) (d) \(0.3 \mathrm{~N}\)
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