Two concentric coils each of radius equal to \(2 \pi \mathrm{cm}\) are placed at right angles to each other. 3 Amp and \(4 \mathrm{Amp}\) are the currents flowing in each coil respectively. The magnetic field intensity at the centre of the coils will be Tesla. (a) \(5 \times 10^{-5}\) (b) \(7 \times 10^{-5}\) (c) \(12 \times 10^{-5}\) (d) \(10^{-5}\)

We will use the Biot-Savart Law to find the magnetic field intensity produced by each coil. The formula for the magnetic field intensity (B) at the center of a circular coil is given by: \[B = \frac{\mu_0 I}{2R}\] where \(\mu_0 = 4\pi \times 10^{-7} Tm/A\) (permeability of free space), \(I\) is the current flowing in the coil, and \(R\) is the radius of the coil. Using the given information, For Coil 1: \(I_1 = 3 A\), \(R = 2\pi cm = 2\pi \times 10^{-2} m\) For Coil 2: \(I_2 = 4 A\), \(R = 2\pi cm = 2\pi \times 10^{-2} m\) Calculate the magnetic field intensity produced by each coil: For Coil 1: \(B_1 = \frac{4\pi \times 10^{-7} (3)}{2(2\pi \times 10^{-2})}\) For Coil 2: \(B_2 = \frac{4\pi \times 10^{-7} (4)}{2(2\pi \times 10^{-2})}\)

Since the coils are placed at right angles to each other, we can think of the net magnetic field intensity as the hypotenuse of a right triangle, where the sides are the individual magnetic field intensities produced by the coils. We can find the net magnetic field intensity (B_net) using the Pythagorean theorem: \[B_{net} = \sqrt{B_1^2 + B_2^2}\] Substitute the values calculated in Step 1 and find \(B_{net}\).

Once we have calculated the net magnetic field intensity at the center of the concentric coils, compare the value with the options given in the problem and choose the closest option.