Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 13: Problem 1964

In the case of bar magnet, lines of magnetic induction (a) Start from the North pole and end at the South pole (b) Run continuously through the bar and outside (c) Emerge in circular paths from the middle of the bar (d) Are produced only at the North pole like rays of light from a bulb.

Short Answer

Expert verified
The correct statements about lines of magnetic induction in the case of a bar magnet are: (a) They start from the North pole and end at the South pole, and (b) They run continuously through the bar and outside, forming closed loops.

Step by step solution

01

Recall the properties of magnetic field lines

Magnetic field lines, or lines of magnetic induction, are used to visualize the magnetic field around a magnet. The following are the general properties of magnetic field lines: 1. Magnetic field lines never intersect each other. 2. They always form closed loops. 3. They emerge from the North pole and enter the South pole of the magnet. 4. The density of the magnetic field lines indicates the strength of the magnetic field. Now, let's analyze each statement in the given exercise and determine which one is correct.
02

Analyze statement (a)

"Start from the North pole and end at the South pole." This statement is correct. As we mentioned in the properties of magnetic field lines, they emerge from the North pole and enter the South pole of the magnet.
03

Analyze statement (b)

"Run continuously through the bar and outside." This statement is also correct. Magnetic field lines form closed loops, which means that they must pass through the magnet and continue outside.
04

Analyze statement (c)

"Emerge in circular paths from the middle of the bar." This statement is incorrect. Magnetic field lines emerge from the North pole, not the middle of the bar.
05

Analyze statement (d)

"Are produced only at the North pole like rays of light from a bulb." This statement is incorrect. Magnetic field lines emerge from the North pole but enter the South pole. They are not only produced at the North pole.
06

Conclusion

Based on our analysis, the correct statements are: (a) Start from the North pole and end at the South pole. (b) Run continuously through the bar and outside.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two straight long conductors \(\mathrm{AOB}\) and \(\mathrm{COD}\) are perpendicular to each other and carry currents \(\mathrm{I}_{1}\) and \(\mathrm{I}_{2}\). The magnitude of the mag. field at a point " \(\mathrm{P}^{n}\) at a distance " \(\mathrm{a}^{\prime \prime}\) from the point "O" in a direction perpendicular to the plane \(\mathrm{ABCD}\) is (a) \(\left[\left(\mu_{0}\right) /(2 \pi a)\right]\left(I_{1}+I_{2}\right)\) (b) \(\left[\left(\mu_{0}\right) /(2 \pi a)\right]\left(I_{1}-I_{2}\right)\) (c) $\left[\left(\mu_{0}\right) /(2 \pi a)\right]\left(\mathrm{I}_{1}^{2}+\mathrm{I}_{2}^{2}\right)^{1 / 2}$ (d) $\left[\left(\mu_{0}\right) /(2 \pi a)\right]\left[\left(I_{1} I_{2}\right) /\left(I_{1}-I_{2}\right)\right]$

If a long hollow copper pipe carries a direct current, the magnetic field associated with the current will be (a) Only inside the pipe (b) Only outside the pipe (c) Neither inside nor outside the pipe (d) Both inside and outside the pipe

An electron moving with a speed \(y_{0}\) along the positive \(x\) -axis at \(\mathrm{y}=0\) enters a region of uniform magnetic field \(\mathrm{B}^{-}=-\mathrm{B}_{0} \mathrm{k} \wedge\) which exists to the right of y-axis. The electron exits from the region after some time with the speed at co-ordinate y then.

A long straight wire of radius "a" carries a steady current I the current is uniformly distributed across its cross-section. The ratio of the magnetic field at \(\mathrm{a} / 2\) and \(2 \mathrm{a}\) is (a) \((1 / 4)\) (b) 4 (c) 1 (d) \((1 / 2)\)

5: When the current flowing in a circular coil is doubled and the number of turns of the coil in it is halved, the magnetic field at its centre will become (a) Four times (b) Same (c) Half (d) Double
See all solutions

Recommended explanations on English Textbooks

Global English

Read Explanation

Essay Writing Skills

Read Explanation

English Grammar Summary

Read Explanation

Email

Read Explanation

Language Analysis

Read Explanation

Textual Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free