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Chapter 14: Problem 2049

The self inductance of a coil is \(5 \mathrm{H}\), a current of \(1 \mathrm{~A}\) changes to \(2 \mathrm{~A}\) within \(5 \mathrm{sec}\). through the coil. The value of induced emf will be \(\ldots \ldots\) (a) \(10 \mathrm{~V}\) (b) \(0.1 \mathrm{~V}\) (c) \(1 \mathrm{~V}\) (d) \(100 \mathrm{~V}\)

Short Answer

Expert verified
The value of induced emf will be (c) 1 V.

Step by step solution

01

Identify the given information

We are given: - Self inductance of the coil, L = 5 H - Current changes from 1 A to 2 A - Time interval, t = 5 seconds
02

Calculate the rate of change of current

To find the rate of change of current, we can use the formula di/dt = (Final current - Initial current) / time interval. So, the rate of change of current is: di/dt = (2 A - 1 A) / 5 seconds = \( \frac{1 \mathrm{~A}}{5 \mathrm{~s}} \)
03

Calculate the induced emf

Now we can use the formula for induced emf, e = L*(di/dt): e = 5 H * \( \frac{1 \mathrm{~A}}{5 \mathrm{~s}} \) = 1 V
04

Find the correct answer

Comparing the calculated induced emf to the available options, the correct answer is: (c) 1 V

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