Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 15: Problem 2148

For an electromagnetic wave, the phase difference between vectors \(\mathrm{E}^{-}\) and \(\mathrm{B}^{-}\) (far away from the source) (A) 0 (B) \([\pi / 2]\) (C) \(\pi\) (D) \([3 \pi / 2]\)

Short Answer

Expert verified
For an electromagnetic wave far away from the source, the electric field vector \(\mathrm{E}^{-}\) and the magnetic field vector \(\mathrm{B}^{-}\) are in phase with each other, meaning they reach their maximum and minimum values simultaneously. Therefore, the phase difference between these vectors is 0. So the correct answer is (A) 0.

Step by step solution

01

Recall the properties of electromagnetic waves

Electromagnetic waves consist of oscillating electric and magnetic fields that are perpendicular to each other and the direction of wave propagation. They travel at the speed of light, and their electric and magnetic fields are related by the equation: \[c = \frac{E}{B}\], where \(c\) is the speed of light, and \(E\) and \(B\) represent the magnitudes of the electric field and magnetic field, respectively.
02

Identify the phase difference between the electric and magnetic fields

In electromagnetic waves, the electric and magnetic fields oscillate sinusoidally and they are in phase with each other. This means that the electric and magnetic fields both reach their maximum and minimum values simultaneously. Therefore, the phase difference between the electric field vector \(\mathrm{E}^{-}\) and the magnetic field vector \(\mathrm{B}^{-}\) is 0.
03

Choose the correct answer

From the given options, the correct answer that represents the phase difference between the electric field vector \(\mathrm{E}^{-}\) and the magnetic field vector \(\mathrm{B}^{-}\) is: (A) 0

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The velocity of light in vacuum can be changed by changing (A) frequency (B) wavelength (C) amplitude (D) none of these

The electromagnetic waves do not transport (A) energy (B) charge (C) momentum (D) information

Which of the following electromagnetic waves has the longest wavelength? (A) Radio waves (B) Infrared radiations (C) x rays (D) visible rays

In microwave oven, we use electromagnetic oscillators which produce electromagnetic waves in the wavelength range (A) \(1 \mathrm{~mm}\) to \(10 \mathrm{~m}\) (B) \(0.7 \mu \mathrm{m}\) to \(1 \mathrm{~mm}\) (C) \(0.1 \mathrm{~m}\) to \(1 \mathrm{~mm}\) (D) \(0.1 \mu \mathrm{m}\) to \(0.7 \mu \mathrm{m}\)

Electromagnetic waves travelling in a medium which has relative permeability \(1.3\) and relative permittivity \(2.14\) speed of electromagnetic waves in this medium will be (A) \(3.6 \times 10^{8} \mathrm{~m} / \mathrm{s}\) (B) \(1.8 \times 10^{8} \mathrm{~m} / \mathrm{s}\) (C) \(1.8 \times 10^{6} \mathrm{~m} / \mathrm{s}\) (D) \(13.6 \times 10^{6} \mathrm{~m} / \mathrm{s}\)
See all solutions

Recommended explanations on English Textbooks

Single Paragraph Essay

Read Explanation

Syntax

Read Explanation

Language Acquisition

Read Explanation

Multiple Choice Questions

Read Explanation

Phonetics

Read Explanation

Essay Plan

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free