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Chapter 15: Problem 2162

If the wavelength of light is \(4000^{\circ} \mathrm{A}\) then the number of waves in \(1 \mathrm{~mm}\) length will be (A) \(2.5\) (B) 2500 (C) 250 (D) 25000

Short Answer

Expert verified
The number of waves in 1 mm length, given the wavelength of light is \(4000^{\circ} \mathrm{A}\), is 25000.

Step by step solution

01

Convert the given units into millimeters

First, we need to convert the given wavelength (in Angstroms) into millimeters. We know that \(1 \mathrm{~A} = 10^{-10} \mathrm{~m}\) and \(1 \mathrm{~mm} = 10^{-3} \mathrm{~m}\). Therefore, to convert Angstroms to millimeters, we can use the following formula: Wavelength (in mm) = Wavelength (in A) × \(10^{-10} \mathrm{~m}\) / \(10^{-3} \mathrm{~m}\) For the given wavelength of \(4000^{\circ} \mathrm{A}\): Wavelength (in mm) = \(4000 \times (10^{-10} / 10^{-3}) = 4000 \times 10^{-7}\) Now, we have the wavelength in mm.
02

Calculate the number of waves

To find the number of waves in 1 mm length, we can use the formula: Number of waves (N) = Length / Wavelength In this case, the Length is 1 mm, and we have already calculated the Wavelength in step 1. Hence, N = 1 mm / (4000 x \(10^{-7}\) mm) N = \(1 / (4000 \times 10^{-7})\) N = \(10^{7} / 4000\) N = 25000
03

Choose the correct answer

The number of waves in 1mm length is 25000. Therefore, the correct answer is: (D) 25000

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Most popular questions from this chapter

Our eyes respond to wavelength ranging from (A) \(400 \mathrm{~nm}\) to \(700 \mathrm{~nm}\) (B) \(-\infty\) to \(+\infty\) (C) \(1 \mathrm{~mm}\) to \(700 \mathrm{~nm}\) (D) \(700 \mathrm{~nm}\) to \(800 \mathrm{~nm}\)

In an electromagnetic wave, if the amplitude of magnetic field is $3 \times 10^{-10} \mathrm{~T}$, the amplitude of the associated electric field will be (A) \(9 \times 10^{-2} \overline{\mathrm{Vm}^{-1}}\) (B) \(3 \times 10^{-10} \mathrm{Vm}^{-1}\) (C) \(3 \times 10^{-2} \mathrm{Vm}^{-1}\) (D) \(1 \times 10^{-18} \mathrm{Vm}^{-1}\)

The waves used in communication are generally called (A) \(\gamma\) rays (B) \(\alpha\) rays (C) microwaves (D) radiowaves

According to Maxwell, a changing electric field produces (A) emf (B) radiation pressure (C) electric current (D) magnetic field

Speed of electromagnetic wave is the same (A) for all wavelengths (B) in all media (C) for all intensities (D) for all frequencies
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