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Chapter 15: Problem 2185

The oscillating electric and magnetic field vectors of an electromagnetic waves far away from source are oriented along (A) Mutually perpendicular direction and differ in phase by \(90^{\circ}\) (B) Mutually perpendicular and in same phase (C) In same direction and in same phase (D) In same direction and differ in phase by \(90^{\circ}\)

Short Answer

Expert verified
The correct answer is (B) Mutually perpendicular and in same phase. This is because the electric and magnetic field vectors in electromagnetic waves are always perpendicular to each other, and they oscillate in phase.

Step by step solution

01

Determine the properties of electromagnetic waves

Electromagnetic waves are waves composed of oscillating electric and magnetic fields. These waves are produced by time-varying electric and magnetic fields, which are always mutually perpendicular to each other. Also, the direction of wave propagation is perpendicular to both field vectors.
02

Understand the relation between the electric and magnetic fields

In electromagnetic waves, the electric field (E) and the magnetic field (B) are in phase, meaning they both reach their maximum and minimum values simultaneously. Far away from the source, electromagnetic waves usually follow the properties of plane waves. This implies that the electric and magnetic fields maintain their mutual perpendicular orientation and in-phase relationship as the electromagnetic wave propagates through space.
03

Choose the correct option

Based on the properties of electromagnetic waves and the relationship between the electric and magnetic fields, we can conclude that the correct answer is: (B) Mutually perpendicular and in same phase. This is because the electric and magnetic field vectors are always perpendicular to each other, and they oscillate in phase in an electromagnetic wave.

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Most popular questions from this chapter

If \(\mathrm{V}_{\mathrm{r}}, \mathrm{V}_{\mathrm{x}}\) and \(\mathrm{V}_{\mathrm{m}}\) are the velocity of the \(\gamma\) rays, \(\mathrm{x}\) rays, micro waves respectively in space, then (A) \(\mathrm{V}_{\gamma}<\mathrm{V}_{\mathrm{x}}<\mathrm{V}_{\mathrm{m}}\) (B) \(\mathrm{V}_{\mathrm{r}}=\mathrm{V}_{\mathrm{x}}=\mathrm{V}_{\mathrm{m}}\) (C) \(\mathrm{V}_{\mathrm{r}}^{\prime}>\mathrm{V}_{\mathrm{x}}>\mathrm{V}_{\mathrm{m}}\) (D) \(\mathrm{V}_{\mathrm{r}}>\mathrm{V}_{\mathrm{x}}<\mathrm{V}_{\mathrm{m}}\)

Electromagnetic wave is produced by oscillating electric and magnetic fields \(E^{-}\) and \(B^{-}\). Choose only the incorrect statement from the following (A) \(\mathrm{E}^{-}\) is perpendicular to \(\mathrm{B}^{-}\). (B) \(E^{-}\) is perpendicular to the direction of propagation of the wave (C) \(\mathrm{B}^{-}\) is perpendicular to the direction of propagation of the wave (D) \(E^{-}\) is parallel to \(\mathrm{B}^{-}\)

If \(\lambda_{\gamma} \lambda_{\mathrm{x}}\) and \(\lambda_{\mathrm{m}}\) are the wave lengths of the \(\gamma\) -rays, \(\mathrm{x}\) rays and micro waves respectively in space then (A) \(\lambda_{\gamma}>\lambda_{\mathrm{x}}>\lambda_{\mathrm{m}}\) (B) \(\lambda_{\gamma}<\lambda_{\mathrm{x}}<\lambda_{\mathrm{m}}\) (C) \(\lambda_{r}=\lambda_{x}=\lambda_{m}\) (D) \(\lambda_{\gamma}<\lambda_{\mathrm{m}}<\lambda_{\mathrm{x}}\)

An electromagnetic wave going through vacuum is described by $E=E_{0} \sin (k x-\cot )$. Which of the following is independent of the wavelength? (A) \(\omega\) (B) \((\mathrm{k} / \mathrm{c})\) (C) \(\mathrm{k}_{\mathfrak{e}}\) (D) \(\mathrm{k}\)

Our eyes respond to wavelength ranging from (A) \(400 \mathrm{~nm}\) to \(700 \mathrm{~nm}\) (B) \(-\infty\) to \(+\infty\) (C) \(1 \mathrm{~mm}\) to \(700 \mathrm{~nm}\) (D) \(700 \mathrm{~nm}\) to \(800 \mathrm{~nm}\)
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