Chapter 15: Problem 2190
SI unit of displacement current is (A) coulomb (B) ampere (C) faraday (D) volt
Chapter 15: Problem 2190
SI unit of displacement current is (A) coulomb (B) ampere (C) faraday (D) volt
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Get started for freeAstronomers have found that electromagnetic waves of wavelength $21 \mathrm{~cm}$ are continuously reaching the Earth's surface. Calculate the frequency of this radiation. $\left(\mathrm{c}=3 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)$ (A) \(14.28 \mathrm{GHz}\) (B) \(1.428 \mathrm{kHz}\) (C) \(1.428 \mathrm{MHz}\) (D) \(1.428 \mathrm{GHz}\)
The frequency of light wave of wavelength \(5000 \mathrm{~A}\) is \(\mathrm{Hz}\) (A) \(6 \times 10^{14}\) (B) \(1.5 \times 10^{-2}\) (C) \(1.5\) (D) \(6 \times 10^{1}\)
Maxwells equations are derived from the laws of (A) electricity (B) magnetism (C) both electricity and magnetism (D) mechanics
The maximum electric field in a plane electromagnetic wave is $900 \mathrm{NC}^{-1}\(. The wave is going in the \)\mathrm{x}$ direction and the electric field is in the y direction. The maximum magnetic field in the wave is \(\mathrm{T}\) (A) \(3 \times 10^{-8}\) (B) \(3 \overline{\times 10^{-6}}\) (C) \(27 \times 10^{-6}\) (D) $27 \times 10^{10}$
The electric and magnetic field of an electromagnetic wave are (A) in phase and perpendicular to each other (B) in phase and parallel to each other (C) in opposite phase and perpendicular to each other (D) in opposite phase and parallel to each other
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