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Chapter 15: Problem 2209

is responsible for the green house effect (A) infrared rays (B) ultraviolet rays (C) x rays (D) radiowaves

Short Answer

Expert verified
(A) Infrared rays are responsible for the greenhouse effect, as they are emitted by the Earth's surface and absorbed and re-emitted by greenhouse gases in the atmosphere, trapping heat and causing the greenhouse effect.

Step by step solution

01

Infrared Rays

Infrared rays are a type of electromagnetic radiation that have longer wavelengths than visible light but shorter wavelengths than microwaves. They are primarily responsible for the heat we feel from the Sun. In the greenhouse effect, infrared radiation is emitted by the Earth's surface after absorbing sunlight. The greenhouse gases in the atmosphere then absorb and re-emit this infrared radiation, trapping heat in the Earth's atmosphere, and causing the greenhouse effect. So, (A) infrared rays are the significant factor for causing the greenhouse effect.
02

Ultraviolet Rays

Ultraviolet rays are a type of electromagnetic radiation with shorter wavelengths than visible light but longer wavelengths than X-rays. They are responsible for causing sunburn and can have harmful effects on living organisms. However, ultraviolet rays do not have a significant role in the greenhouse effect. Hence, (B) ultraviolet rays are not responsible for the greenhouse effect.
03

X Rays

X rays are a type of electromagnetic radiation with shorter wavelengths than both ultraviolet rays and visible light. They are used in medical imaging and other scientific applications. X rays do not have any significant role in the greenhouse effect. Therefore, (C) X rays are not responsible for the greenhouse effect.
04

Radiowaves

Radiowaves are a type of electromagnetic radiation with the longest wavelength. They are used for communication purposes, such as with radios, televisions, and cell phones. Radiowaves do not play any role in the greenhouse effect. So, (D) radiowaves are not responsible for the greenhouse effect. With all the options analyzed, we can now determine the correct answer.
05

Conclusion

Based on our discussion, it is clear that (A) infrared rays are responsible for the greenhouse effect. Therefore, the correct answer is (A) infrared rays.

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Most popular questions from this chapter

Electromagnetic waves are produced by (A) a static charge (B) a moving charge (C) an accelerating charge (D) chargeless particles

The amplitude of the magnetic field part of an electromagnetic wave in vacuum is \(\mathrm{Bm}=510 \mathrm{nT}\). Then the amplitude of the electric part of the wave is (A) \(1.53 \times 10^{11} \mathrm{~V} / \mathrm{m}\) (B) \(1.53 \mathrm{~V} / \mathrm{m}\) (C) \(1.53 \times 10^{2} \mathrm{~V} / \mathrm{m}\) (D) \(1.53 \times 10^{8} \mathrm{~V} / \mathrm{m}\)

Electromagnetic wave is produced by oscillating electric and magnetic fields \(E^{-}\) and \(B^{-}\). Choose only the incorrect statement from the following (A) \(\mathrm{E}^{-}\) is perpendicular to \(\mathrm{B}^{-}\). (B) \(E^{-}\) is perpendicular to the direction of propagation of the wave (C) \(\mathrm{B}^{-}\) is perpendicular to the direction of propagation of the wave (D) \(E^{-}\) is parallel to \(\mathrm{B}^{-}\)

A plane electromagnetic wave of frequency \(25 \mathrm{MHz}\) travels in free space along the \(\mathrm{x}\) direction. At a particular point in space and time \(\mathrm{E}^{-}=6.3 \mathrm{j} \wedge \mathrm{Vm}^{-1}\) then \(\mathrm{B}^{-}\) at this point is (A) \(2.1 \times 10^{-8}\) i \(\mathrm{T}\) (B) \(2.1 \times 10^{-8} \mathrm{k} \wedge \mathrm{T}\) (C) \(1.89 \times 10^{9} \mathrm{k} \wedge \mathrm{T}\) (D) \(2.52 \times 10^{-7} \mathrm{k} \wedge \mathrm{T}\)

An observer is at \(2 \mathrm{~m}\) from an isotropic point source of light emitting \(40 \mathrm{w}\) power. The rm.s value of electric due to the source at the position of the observer is (A) \(5.77 \times 10^{-8} \mathrm{Vm}^{-1}\) (B) \(17.3 \mathrm{Vm}^{-1}\) (C) \(57.7 \times 10^{-8} \mathrm{Vm}^{-1}\) (D) \(1.73 \mathrm{Vm}^{-1}\)
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