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Chapter 16: Problem 2214

A ray of light is incident at an angle \(30^{\circ}\) on a mirror, The angle between normal and reflected ray is (A) \(15^{\circ}\) (B) \(30^{\circ}\) (C) \(45^{\circ}\) (D) \(60^{\circ}\)

Short Answer

Expert verified
The angle between the normal and the reflected ray is \(60^{\circ}\), corresponding to option (D).

Step by step solution

01

Write down the given information

We are given that the angle of incidence, which we will denote as \(i\), is \(30^{\circ}\). We are tasked with finding the angle between the normal and reflected ray.
02

Apply the law of reflection

According to the law of reflection, the angle of incidence is equal to the angle of reflection. This means that the angle of reflection, which we will denote as \(r\), is also \(30^{\circ}\).
03

Calculate the angle between the normal and reflected ray

Since we know that both the angle of incidence and the angle of reflection are \(30^{\circ}\) and the normal is perpendicular to the mirror, the angle between the normal and the reflected ray can be found by calculating the sum of the angle of incidence and the angle of reflection: \(30^{\circ} + 30^{\circ} = 60^{\circ}\) Therefore, the angle between the normal and the reflected ray is \(60^{\circ}\), which corresponds to option (D).

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