Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 16: Problem 2226

If thin prism of \(5^{\circ}\) gives a deviation of \(2^{\circ}\) then the refractive index of material of prism is (A) \(1.4\) (B) \(1.5\) (C) \(1.6\) (D) \(1.0\)

Short Answer

Expert verified
The refractive index of the material of the prism is approximately \(1.4\) (option A).

Step by step solution

01

Identify given values

We are given the prism angle, \(A=5^{\circ}\), and the deviation, \(δ=2^{\circ}\).
02

Use the deviation in a thin prism formula

To find the refractive index \(n\) of the material, we will use the formula \(δ = (n-1)A\). Plug the given values into the formula: \( 2 = (n - 1)(5) \).
03

Solve for the refractive index, n

Now, solve for \(n\) from the equation: \( 2 = 5(n-1) \) First, divide both sides by 5: \( \frac{2}{5} = n - 1 \) Next, add 1 to both sides of the equation: \( n = \frac{2}{5} + 1 = \frac{7}{5} \) Finally, convert the fraction to a decimal (rounded to one decimal place): \( n \approx 1.4 \) Therefore, the refractive index of the material of the prism is approximately 1.4, which corresponds to option (A).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The head light of a jeep are \(1.2 \mathrm{~m}\) apart. If the pupil of the eye of an observer has a diameter of \(2 \mathrm{~mm}\) and light of wavelength \(5896 \AA\) is used what should be the maximum distance of the jeep from the observer if two head lights are just seem to be separated apart? (A) \(30.9 \mathrm{~km}\) (B) \(33.4 \mathrm{~km}\) (C) \(3.34 \mathrm{~km}\) (D) \(30.9 \mathrm{~km}\)

In a fraunhofer diffraction by single slit of width d with incident light of wavelength \(5500 \AA\) the first minimum is observed at angle of \(30^{\circ}\). The first secondary maximum is observed at an angle \(\theta=\) (A) \(\sin ^{-1}(1 / \sqrt{2})\) (B) \(\sin ^{-1}(3 / 4)\) (C) \(\sin ^{-1}(\sqrt{3} / 2)\) (D) \(\sin ^{-1}(1 / 4)\)

A Slit of width \(12 \times 10^{-7} \mathrm{~m}\) is illuminated by light of wavelength \(6000 \AA\). The angular width of the central maxima is approximately (A) \(30^{\circ}\) (B) \(60^{\circ}\) (C) \(90^{\circ}\) (D) \(0^{\circ}\)

Angle of minimum deviation for a prism refractive index \(1.5\) is equal to the angle of the prism. Then the angle of prism (given, $\sin 48^{\circ} 36^{\prime}=0.75$ ) (A) \(62^{\circ}\) (B) \(82^{\circ}\) (C) \(60^{\circ}\) (D) \(41^{\circ}\)

Mono chromatic light of wavelength \(399 \mathrm{~nm}\) is incident from air on a water \((\mathrm{n}=1.33)\) Surface. The wavelength of refracted light is \(\mathrm{nm}\) (A) 300 (B) \(\overline{600}\) (C) 333 (D) 443
See all solutions

Recommended explanations on English Textbooks

Single Paragraph Essay

Read Explanation

Language and Social Groups

Read Explanation

English Grammar Summary

Read Explanation

Prosody

Read Explanation

Email

Read Explanation

Language Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free