When the length of microscope tube increases, its magnifying power (A) decreases (B) increase (C) does not change (D) none of these

Short Answer

Expert verified
When the length of the microscope tube (L) increases, the term L/\(f_o\) in the magnifying power formula \(M = (1+\frac{L}{f_o})(\frac{25cm}{f_e})\) will also increase, assuming that the focal length of the objective lens (\(f_o\)) remains constant. As a result, the magnifying power (M) will increase. The correct answer is (B) increase.

Step by step solution

01

Understand the formula for magnifying power of a microscope

The formula for the magnifying power (M) of a microscope is given by: \(M = (1+\frac{L}{f_o})(\frac{25cm}{f_e})\) where L is the length of the microscope tube, \(f_o\) is the focal length of the objective lens, and \(f_e\) is the focal length of the eyepiece (all in centimeters).
02

Analyze the effect of a change in tube length on magnifying power

According to the formula, M is proportional to 1+L/\(f_o\). If the length L of the microscope tube increases, the term L/\(f_o\) will also increase as long as the focal length of the objective lens (\(f_o\)) remains constant. Since the rest of the formula remains constant, the overall magnifying power will increase as well.
03

Identify the correct answer

Based on our analysis in Step 2, when the length of the microscope tube increases, the magnifying power of the microscope increases as well. So, the correct answer is: (B) increase

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Light of wave-length \(\lambda\) is incident on a slit of width \(\mathrm{d}\). The resulting diffraction pattern is observed on a screen placed at a distance \(\mathrm{D}\). The linear width of the principal maximum is equal to the width of the slit, then \(\mathrm{D}=\) (A) \(\left(\mathrm{d}^{2} / 2 \lambda\right)\) (B) \(\left(2 \lambda^{2} / \mathrm{d}\right)\) (C) \((\mathrm{d} / \lambda)\) (D) \((2 \lambda / \mathrm{d})\)

In young's double slit experiment, phase difference between light waves reaching 3rd bright fringe from central fringe with, is \((\lambda=5000 \AA)\) (A) zero (B) \(2 \pi\) (C) \(4 \pi\) (D) \(6 \pi\)

A convex lens of glass \((\mathrm{n}=1.5)\) has focal length \(0.2 \mathrm{~m}\). The lens is immersed in water of refractive index \(1.33\). The change in the power of convex lens is (A) \(3.72 \mathrm{D}\) (B) \(4.62 \mathrm{D}\) (C) \(6.44 \mathrm{D}\) (D) \(1.86 \mathrm{D}\)

Which of the following phenomenon is used in optical fibers? (A) Reflection (B) Scattering (C) Total internal refraction (D) Interference

Two thin lenses of focal length \(\mathrm{f}_{1}\) and \(\mathrm{f}_{2}\) are coaxially placed in contact with each other then the power of combination is (A) \(\left[\left(\mathrm{f}_{1}+\mathrm{f}_{2}\right) / 2\right]\) (B) \(\sqrt{\left(f_{1} / f_{2}\right)}\) (C) $\left[\left(\mathrm{f}_{1} \mathrm{f}_{2}\right) /\left(\mathrm{f}_{1}+\mathrm{f}_{2}\right)\right]$ (D) $\left[\left(\mathrm{f}_{1}+\mathrm{f}_{2}\right) /\left(\mathrm{f}_{1} \mathrm{f}_{2}\right)\right]$

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free