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Chapter 16: Problem 2267

The magnifying power of objective of a compound microscope is \(5.0\) If the magnifying power of microscope is 30 , then magnifying power of eye-piece will be (A) 3 (B) 6 (C) 9 (D) 12

Short Answer

Expert verified
The magnifying power of the eyepiece (M_ep) can be found using the formula: Magnifying Power (M) = Magnifying Power of Objective (M_obj) × Magnifying Power of Eyepiece (M_ep). Given the magnifying power of the microscope (M = 30) and the magnifying power of the objective lens (M_obj = 5.0), we can solve for M_ep: M_ep = 30 / 5.0, which gives M_ep = 6. The correct option is (B).

Step by step solution

01

The basic formula used to determine the magnifying power of a compound microscope is: Magnifying Power (M) = Magnifying Power of Objective (M_obj) × Magnifying Power of Eyepiece (M_ep) In this problem, we have M = 30 and M_obj = 5.0. We need to find the value of M_ep. #Step 2: Solve for M_ep#

Plug the given values into the formula and solve for M_ep: 30 = 5.0 × M_ep To isolate M_ep, divide both sides of the equation by 5.0: M_ep = 30 / 5.0 #Step 3: Calculate M_ep#
02

Perform the division: M_ep = 6 #Step 4: Match the answer with the options#

The calculated magnifying power of the eyepiece (M_ep) is 6. Compare this result with the given options: (A) 3 (B) 6 (C) 9 (D) 12 The correct option is (B).

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