Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 17: Problem 2424

According to Rayleigh and Jeans the black body radiation in the cavity is system of (A) progressive electromagnetic waves (B) standing electromagnetic waves (C) electromagnetic waves of discrete (D) standing waves in lattice frequencies

Short Answer

Expert verified
According to Rayleigh and Jeans, the black body radiation in a cavity is described by (B) standing electromagnetic waves. This is due to the boundary conditions inside the cavity and the Rayleigh-Jeans Law, which is based on classical electromagnetic wave theory.

Step by step solution

01

Understanding the Rayleigh-Jeans Law

The Rayleigh-Jeans Law is an attempt to describe the spectral distribution of energy in a black-body radiation. It gives the energy density of radiation in a cavity per unit frequency range. This law is based on classical electromagnetic wave theory, combined with statistical mechanics, and is given by the expression: \[u(\nu, T) = \frac{8\pi\nu^2}{c^3} k_BT\] Where \(u(\nu, T)\) is the energy density per unit frequency, \(\nu\) is the frequency, \(T\) is the temperature, \(c\) is the speed of light, and \(kB\) is the Boltzmann constant.
02

Identifying the nature of waves from the Rayleigh-Jeans Law

Since Rayleigh-Jeans Law is based on classical electromagnetic wave theory, it implies that the black body radiation is essentially a result of the interaction between electromagnetic waves bouncing around within the cavity. The waves will form standing wave patterns due to the boundary conditions inside the cavity.
03

Choose the correct description

According to our analysis of the Rayleigh-Jeans Law and its implications for black-body radiation in a cavity, the correct answer should be: (B) standing electromagnetic waves

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Energy of a particle having de-Broglie wavelength \(0.004 \AA\) is... (A) \(1280 \mathrm{eV}\) (B) \(1200 \mathrm{eV}\) (C) \(1200 \mathrm{MeV}\) (D) \(1200 \mathrm{GeV}\)

An image of sun is formed by a lens of focal length \(30 \mathrm{~cm}\) on the metal surface of a photo-electric cell and a photoelectric current (I) is produced. The lens forming the image is then replaced by another of the same diameter but of focal length of \(15 \mathrm{~cm}\). The photoelectric current in this case is \(\ldots \ldots \ldots\) (A) \((1 / 2)\) (B) 1 (C) \(2 \mathrm{I}\) (D) \(4 \mathrm{I}\)

De-Broglie wavelength of particle moving at a (1/4) th of speed of light having rest mass \(\mathrm{m}_{0}\) is \(\ldots \ldots \ldots\) (A) $\left\\{(3.87 \mathrm{~h}) /\left(\mathrm{m}_{0} \mathrm{C}\right)\right\\}$ (B) $\left\\{(4.92 \mathrm{~h}) /\left(\mathrm{m}_{0} \mathrm{C}\right)\right\\}$ (C) $\left\\{(7.57 \mathrm{~h}) /\left(\mathrm{m}_{0} \mathrm{C}\right)\right\\}$ (D) $\left\\{(9.46 \mathrm{~h}) /\left(\mathrm{m}_{\circ} \mathrm{C}\right)\right\\}$

Suppose \(\Psi(\mathrm{x}, \mathrm{y}, \mathrm{z})\) represents a particle in three dimensional space, then probability of finding the particle in the unit volume at a given point \(\mathrm{x}, \mathrm{y}, \mathrm{z}\) is $\ldots \ldots$ (A) inversely proportional to $\Psi^{\prime}(\mathrm{x}, \mathrm{y}, \mathrm{z})$ (B) directly proportional \(\Psi^{*}\) (C) directly proportional to \(\mid \Psi \Psi^{*}\) (D) inversely proportional to \(\left|\Psi \Psi^{*}\right|\)

Direction Read the following question choose if: (a) Both Assertion and Reason are true and Reason is correct explanation of Assertion. (b) Both Assertion and Reason are true, but Reason is not correct explanation of Assertion. (c) Assertion is true but the Reason is false. (d) Both Assertion and Reason is false. Assertion : The de Broglie wavelength of an electron accelerated through 941 volts is \(0.4 \AA\). Reason: Higher the acceleration potentials of electron, smaller is the de Broglie wavelength. (A) a (B) \(\mathrm{b}\) (C) (D) \(\mathrm{d}\)
See all solutions

Recommended explanations on English Textbooks

Rhetorical Analysis Essay

Read Explanation

Summary Text

Read Explanation

Morphology

Read Explanation

Creative Story

Read Explanation

Free Response Essay

Read Explanation

5 Paragraph Essay

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free