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Chapter 18: Problem 2493

when \({ }_{3}^{7}\) Li nuclear are bombarded by Proton and the resultant nuclei are \({ }^{8}{ }_{4}\) Be, the emitted particle will be (A) neutron (B) gamma (C) alpha (D) Beta

Short Answer

Expert verified
The emitted particle in the given nuclear reaction is a gamma photon. The correct answer is (B) gamma.

Step by step solution

01

Write down the nuclear reaction

We are given that a Lithium-7 nucleus is bombarded by a proton, resulting in a Beryllium-8 nucleus, emitting a particle X. The nuclear reaction can be written as: \[^{7}_{3}\textrm{Li} + ^{1}_{1}\textrm{P} \rightarrow ^{8}_{4}\textrm{Be} + \textrm{X}\]
02

Conserve the nucleons

Next, we will apply the Law of Conservation of nucleons. The total number of nucleons on the left side of the reaction should equal the total number of nucleons on the right side. From the given reaction, we can see that the number of protons and neutrons are: - Left side: Protons: 3 + 1 = 4 Neutrons: (7-3) + (1-1) = 4 - Right side: Protons: 4 + (x protons in particle X) Neutrons: (8-4) + (y neutrons in particle X) Now, equate both sides: 4 protons = 4 + x protons 4 neutrons = 4 + y neutrons
03

Determine the emitted particle

From the above equations, we can deduce the number of protons and neutrons in particle X: x = 0 (No additional protons) y = 0 (No additional neutrons) So, particle X has 0 protons and 0 neutrons, which corresponds to a gamma photon in this case. Therefore, the emitted particle is a gamma photon. The correct answer is (B) gamma.

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Most popular questions from this chapter

when \(u-238\) nucleus originally at rest decay by emitting an \(\alpha\) -particle having a speed u the recoil speed of the residual nucleus is. (A) \([(4 \mathrm{u}) /(238)]\) (B) \([(-4 \mathrm{u}) /(238)]\) (C) \([(4 \mathrm{u}) /(234)]\) (D) \([(-4 \mathrm{u}) /(234)]\)

Read the following question and choose correct Answer form given below. (A) Both assertion and reason are true. Reason is the correct explanation of the Assertion. (B) Both assertion and reason are true. Reason is not correct explanation of the assertion. (C) Assertion is true but reason is false. (D) Assertion is false and Reason are true. (i) Assertion :- In a radio-active disintegration, an electron is emitted by nucleus. Reason :- electron are always Present in-side the nucleus. (ii) Assertion :- An electron and Positron can annihilate each other creating Photon Reason:- Electron and Positron form a Particle and anti Particle pair. (iii) Assertion:- An isolated radioactive atom may not decay at all what ever be its half time Reason:- Radioactive decay is a statistical Phenomena. (iv) Assertion:- Fragment Produced in the fission of \(\mathrm{u}^{235}\) are active Reason:- The fragments have abnormally high Proton to neutron ratio

The hydrogen atom can give spectral lines in the series Lyman, Balmer and Paschen. which of the following statement is correct (A) Lyman series is in the infrared region (B) Balmer series is in the ultraviolet region (C) Balmer series is in the visible region (D) Paschen series is in the visible region.

In which region of electromagnetic spectrum does the Lyman series of hydrogen atom like (A) \(x\) -ray (B) Infrared (C) visible (D) ultraviolet

which of these is a fusion reaction (A) ${ }^{3}{ }_{1} \mathrm{H}+{ }_{1}^{2} \mathrm{H}={ }_{2}^{4} \mathrm{He}+{ }_{0} \mathrm{n}^{1}$ (B) ${ }^{12}{ }_{7} \mathrm{C} \rightarrow{ }_{6} \mathrm{C}^{12}+\beta^{+}+\mathrm{g}$ (C) ${ }_{92} \mathrm{U}^{238} \rightarrow{ }^{206}{ }_{82} \mathrm{~Pb}+8\left({ }_{2}^{4} \mathrm{He}\right)+6\left(_{1-} \mathrm{e}\right)$ (D) None of these
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