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Chapter 18: Problem 2493

when \({ }_{3}^{7}\) Li nuclear are bombarded by Proton and the resultant nuclei are \({ }^{8}{ }_{4}\) Be, the emitted particle will be (A) neutron (B) gamma (C) alpha (D) Beta

Short Answer

Expert verified
The emitted particle in the given nuclear reaction is a gamma photon. The correct answer is (B) gamma.

Step by step solution

01

Write down the nuclear reaction

We are given that a Lithium-7 nucleus is bombarded by a proton, resulting in a Beryllium-8 nucleus, emitting a particle X. The nuclear reaction can be written as: \[^{7}_{3}\textrm{Li} + ^{1}_{1}\textrm{P} \rightarrow ^{8}_{4}\textrm{Be} + \textrm{X}\]
02

Conserve the nucleons

Next, we will apply the Law of Conservation of nucleons. The total number of nucleons on the left side of the reaction should equal the total number of nucleons on the right side. From the given reaction, we can see that the number of protons and neutrons are: - Left side: Protons: 3 + 1 = 4 Neutrons: (7-3) + (1-1) = 4 - Right side: Protons: 4 + (x protons in particle X) Neutrons: (8-4) + (y neutrons in particle X) Now, equate both sides: 4 protons = 4 + x protons 4 neutrons = 4 + y neutrons
03

Determine the emitted particle

From the above equations, we can deduce the number of protons and neutrons in particle X: x = 0 (No additional protons) y = 0 (No additional neutrons) So, particle X has 0 protons and 0 neutrons, which corresponds to a gamma photon in this case. Therefore, the emitted particle is a gamma photon. The correct answer is (B) gamma.

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Most popular questions from this chapter

An electron change its Position from orbit \(n=4\) to the orbit \(\mathrm{n}=2\) of an atom the wave length of emitted radiation in the form of \(\mathrm{R}\) (where \(\mathrm{R}\) is Redburg constants) (A) \((16 / 7 \mathrm{R})\) (B) \((16 / \mathrm{R})\) (C) (16 / 3R) (D) \((16 / 5 \mathrm{R})\)

The radio of minimum to maximum wave length in Balmer series is (A) \((1 / 4)\) (B) \((5 / 36)\) (C) \((3 / 4)\) (D) \((5 / 9)\)

which of the following isotopes normally fissionable (A) \({ }_{92} \mathrm{U}^{233}\) (B) \({ }_{92} \mathrm{U}^{238}\) (C) \({ }_{92} \mathrm{U}^{235}\) (D) \({ }_{93} \mathrm{~Np}^{239}\)

In terms of Rydberg constant \(R\). The wave number of first Balmer line is (A) \((5 \mathrm{R} / 36)\) (B) \((8 \mathrm{R} / 9)\) (C) \(\mathrm{R}\) (D) \((8 \mathrm{R} / 20)\)

Match column I and II column I \(\frac{\text { column I }}{\text { fnucleus }}\) (a) size of (b) number of Proton in a nucleus column II (p) Z (q) \(10^{-15} \mathrm{~m}\) (r) \((\mathrm{A}-\mathrm{Z})\) (s) \(10^{-10} \mathrm{~m}\) 0 (c) size of Atom (d) Number of neutrons in a nucleus (A) $\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{s}, \mathrm{c} \rightarrow \mathrm{q}, \mathrm{d} \rightarrow \mathrm{p}$ (B) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{p}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{r}$ (C) $\mathrm{a} \rightarrow \mathrm{s}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{q}, \mathrm{d} \rightarrow \mathrm{p}$ (D) $\mathrm{b} \rightarrow \mathrm{s}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{c} \rightarrow \mathrm{q}, \mathrm{d} \rightarrow \mathrm{r}$
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