which of these is a fusion reaction (A) ${ }^{3}{ }_{1} \mathrm{H}+{ }_{1}^{2} \mathrm{H}={ }_{2}^{4} \mathrm{He}+{ }_{0} \mathrm{n}^{1}$ (B) ${ }^{12}{ }_{7} \mathrm{C} \rightarrow{ }_{6} \mathrm{C}^{12}+\beta^{+}+\mathrm{g}$ (C) ${ }_{92} \mathrm{U}^{238} \rightarrow{ }^{206}{ }_{82} \mathrm{~Pb}+8\left({ }_{2}^{4} \mathrm{He}\right)+6\left(_{1-} \mathrm{e}\right)$ (D) None of these

Short Answer

Expert verified
The correct answer is (A) \({ }^{3}{ }_{1} \mathrm{H}+{ }_{1}^{2} \mathrm{H}={ }_{2}^{4}\mathrm{He}+{ }_{0} \mathrm{n}^{1}\) as this is a fusion reaction involving the combination of tritium and deuterium nuclei to form a heavier helium-4 nucleus and a neutron.

Step by step solution

01

Analyze each reaction type

Let's analyze each given reaction to determine if it is a fusion reaction. (A) \({ }^{3}{ }_{1} \mathrm{H}+{ }_{1}^{2} \mathrm{H}={ }_{2}^{4}\mathrm{He}+{ }_{0} \mathrm{n}^{1}\) Here, we have two atomic nuclei, tritium (\({ }^{3}{ }_{1} \mathrm{H}\)) and deuterium (\({ }_{1}^{2} \mathrm{H}\)), combining to form a single heavier nucleus, helium-4 (\({ }_{2}^{4}\mathrm{He}\)), and a neutron. This seems like a fusion reaction. (B) \({ }^{12}{ }_{7} \mathrm{C} \rightarrow{ }_{6}\mathrm{C}^{12}+\beta^{+}+\mathrm{g}\) In this reaction, one nucleus, carbon with a mass number of 12 and an atomic number of 7 (\({ }^{12}{ }_{7} \mathrm{C}\)), is decaying into another nucleus, carbon with a mass number of 12 and an atomic number of 6 (\({ }_{6}\mathrm{C}^{12}\)), while also emitting a positron (\(\beta^{+}\)) and a photon (g). This type of reaction is not fusion, as there's no combining of atomic nuclei. (C) \({ }_{92} \mathrm{U}^{238} \rightarrow{ }^{206}{ }_{82}\mathrm{~Pb}+8\left({ }_{2}^{4} \mathrm{He}\right)+6\left(_{1-}\mathrm{e}\right)\) In this reaction, a uranium-238 nucleus (\({ }_{92} \mathrm{U}^{238}\)) is breaking apart into a lead-206 nucleus (\({ }^{206}{ }_{82}\mathrm{~Pb}\)), eight helium-4 nuclei, and six electrons. This is a fission reaction, not fusion, as the initial nucleus is splitting into smaller ones.
02

Determine the correct answer

Now that we analyzed each reaction, we can confidently say that the correct answer is: (A) \({ }^{3}{ }_{1} \mathrm{H}+{ }_{1}^{2} \mathrm{H}={ }_{2}^{4}\mathrm{He}+{ }_{0} \mathrm{n}^{1}\) This is a fusion reaction because two atomic nuclei, tritium and deuterium, combine to form a single heavier nucleus, helium-4, and a neutron.

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Most popular questions from this chapter

The half life time of a radioactive elements of \(\mathrm{x}\) is the same as the mean life of another radioactive element \(\mathrm{y}\). Initially they have same number of atoms, then (A) \(\mathrm{y}\) will decay faster then \(\mathrm{x}\) (B) \(\mathrm{x}\) will decay faster then \(\mathrm{y}\) (C) \(\mathrm{x}\) and \(\mathrm{y}\) will decay at the same rate at all time (D) \(\mathrm{x}\) and \(\mathrm{y}\) will decay at the same rate initially.

The transition the state \(\mathrm{n}=4\) to \(\mathrm{n}=1\) in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition form (A) \(3 \rightarrow 2\) (B) \(5 \rightarrow 4\) (C) \(4 \rightarrow 2\) (D) \(2 \rightarrow 1\)

In gamma ray emission form a nucleus (A) there is no change in the proton-number and neutron number (B) Both the number are changes (C) only Proton number change (D) only neutron number change

two deuterons each of mass \(\mathrm{m}\) fuse to form helium resulting in release of energy \(\mathrm{E}\) the mass of helium formed is (A) \(\mathrm{m}+\left(\mathrm{E} / \mathrm{C}^{2}\right)\) (B) \(\left[\mathrm{E} /\left(\mathrm{mC}^{2}\right)\right]\) (C) \(2 \mathrm{~m}-\left(\mathrm{E} / \mathrm{C}^{2}\right)\) (D) \(2 \mathrm{~m}+\left(\mathrm{E} / \mathrm{C}^{2}\right)\)

If a hydrogen atom emits a Photon of wave length \(\lambda\). the recoil speed of the atom of mass \(\mathrm{m}\) is given by (A) \((\mathrm{h} / \mathrm{m} \lambda)\) (B) \((\mathrm{mh} / \lambda)\) (C) \(\operatorname{mh} \lambda\) (D) \((\mathrm{m} \lambda / \mathrm{h})\)

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