Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 18: Problem 2514

The energy released by the fission of one uranium atom is \(200 \mathrm{MeV}\). The number of fission Per second required to Produce \(3.2 \mathrm{w}\) of Power is (A) \(10^{10}\) (B) \(10^{7}\) (C) \(10^{12}\) (D) \(10^{11}\)

Short Answer

Expert verified
The number of fission per second required to produce 3.2 W of power is approximately \(10^{12}\) fissions/s (Option C).

Step by step solution

01

Convert the energy released per fission to Joules

We are given that the energy released by the fission of one uranium atom is 200 MeV. To convert MeV to Joules, we use the conversion factor 1 MeV = \(1.602\times10^{-13}\) Joules. So, the energy released per fission is: 200 MeV * \((1.602\times10^{-13}) \dfrac{J}{MeV}\) = \(3.204\times10^{-11}\) Joules.
02

Convert the power output to Joules per second

The given power output is 3.2 W. Since 1 Watt is equal to 1 Joule per second, the power output is already in the required unit. Power output = 3.2 J/s.
03

Use the formula Power = Energy / Time to find the number of fissions required per second

To find the number of fissions per second required, we will use the formula Power = Energy / Time. We have the power output and the energy released per fission, so we can plug these values into the formula and solve for the number of fissions: 3.2 J/s = \((3.204\times10^{-11} \mathrm{J/fission}) \times (\mathrm{number\ of \ fissions/s})\) Now, we'll solve for the number of fissions per second: \(\mathrm{number\ of \ fissions/s}\) = \(\dfrac{3.2 \mathrm{J/s}}{3.204\times10^{-11} \mathrm{J/fission}}\) = \(9.98753\times10^{10}\) fissions/s.
04

Choose the closest answer from the given options

Since the number of fissions per second required is approximately \(9.98753\times10^{10}\) fissions/s, the closest option among the given choices is: (C) \(10^{12}\) fissions/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

It the radius of a nucleus of mass number 3 is \(\mathrm{R}\). then the radius of a nucleus of mass number 81 is (A) \(27 \mathrm{R}\) (B) \(9 \mathrm{R}\) (C) \(3 \mathrm{R}\) \((\mathrm{D})(27)^{(1 / 2)} \mathrm{R}\)

excited hydrogen atom emits a Photon of wave length \(\lambda\) in returning to the ground state The quantum number \(\mathrm{n}\) of excited state is given by (A) \(\sqrt{[}(\lambda . \mathrm{R}-1) /(\lambda \mathrm{R})]\) (B) \(\sqrt{[}(\lambda \mathrm{R}) /(\lambda \mathrm{R}-1)]\) (C) \(\sqrt{[\lambda R}(\lambda \mathrm{R}-1)]\) (D) \(\lambda \mathrm{R}(\mathrm{R}-1)\)

Energy levels \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) of a certain atom corresponding values of energy i.e. \(E_{A}

In the following nuclear fusion reaction ${ }_{1}^{2} \mathrm{H}+{ }_{1}^{3} \mathrm{H} \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{0} \mathrm{n}^{1}$ the repulsive potential energy between the two fusing nuclei is $7.7 \times 10^{-14} \mathrm{~J}$. The Temperature to which the gas must be heated is nearly (Boltzman constant \(\mathrm{K}=1.38 \times 10^{-23} \mathrm{JK}^{-1}\) ) (A) \(10^{3} \mathrm{~K}\) (B) \(10^{5} \mathrm{~K}\) (C) \(10^{7} \mathrm{~K}\) (D) \(10^{9} \mathrm{~K}\)

A Free neutron decays into a Proton, an electron and (A) \(\mathrm{v}\) (B) \(\underline{\mathrm{V}}\) (C) \(\beta\) (D) \(\alpha\)
See all solutions

Recommended explanations on English Textbooks

Sociolinguistics

Read Explanation

Rhetorical Analysis Essay

Read Explanation

Essay Plan

Read Explanation

Blog

Read Explanation

Lexis and Semantics Summary

Read Explanation

History of English Language

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free