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Chapter 18: Problem 2535

\({ }_{6} \mathrm{C}^{12}\) absorbs an energetic neutron and emits a \(\beta\) Particle. The resulting nucleus is (A) \({ }_{7} \mathrm{~N}^{13}\) (B) \({ }_{7} \mathrm{~N}^{14}\) (C) \({ }_{6} \mathrm{C}^{13}\) (D) \({ }_{6} \mathrm{C}^{12}\)

Short Answer

Expert verified
The resulting nucleus after the absorption of a neutron and emission of a beta particle is \({ }_{7} \mathrm{N}^{13}\). The correct answer is option (A).

Step by step solution

01

Identify the initial nucleus

The initial nucleus given in the problem is Carbon-12, which can be written as \({ }_{6} \mathrm{C}^{12}\). This means that it has 6 protons and 6 neutrons (12-6=6).
02

Absorption of a neutron

When the Carbon-12 nucleus absorbs a neutron, its neutron count increases by 1. So, the new nucleus will have 6 protons and 7 neutrons, making it Carbon-13 (\({ }_{6} \mathrm{C}^{13}\)).
03

Emission of a beta particle

A beta particle is an electron that is emitted during a beta decay process, in which a neutron changes into a proton. In this reaction, one of the 7 neutrons will change into a proton, so the resulting nucleus will have 7 protons and 6 neutrons (7+6=13).
04

Identify the final nucleus

The final nucleus will have 7 protons and 6 neutrons, which corresponds to Nitrogen-13. Hence, the resulting nucleus after the absorption of a neutron and emission of a beta particle is \({ }_{7} \mathrm{N}^{13}\). So, the correct answer is option (A) \({ }_{7} \mathrm{~N}^{13}\).

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Most popular questions from this chapter

(i) statement-I :- Large angle scattering of alpha Particle led to discovery of atomic nucleus. statement-II :- Entire Positive charge of atom is concentrated in the central core. (A) statement -I and II are true. and statement II is correct explanation of statement-I (B) statement -I and II are true, but statement-II is not correct explanation of statement I (C) statement I is true, but statement II is false. (D) statement I is false but statement II is true (ii) statement-I \(1 \mathrm{amu}=931.48 \mathrm{MeV}\) statement-II It follows form \(E=m c^{2}\) (iii) statement -I:- half life time of tritium is \(12.5\) years statement-II:- The fraction of tritium that remains after 50 years is \(6.25 \%\) (iv) statement-I:- Nuclei of different atoms have same size statement-II:- \(\mathrm{R}=\operatorname{Ro}(\mathrm{A})^{1 / 3}\)

The energy difference between the first two levels of hydrogen atom is $10.2 \mathrm{eV}$. what is the corresponding energy difference for a singly ionized helium atom? (A) \(10.2 \mathrm{eV}\) (B) \(81.6 \mathrm{eV}\) (C) \(20.4 \mathrm{eV}\) (D) \(40.8 \mathrm{eV}\)

which of the following atom has the lowest ionization potential? (A) \({ }^{14}{ }_{7} \mathrm{~N}\) (B) \({ }^{40}{ }_{18} \mathrm{Ar}\) (C) \({ }^{133} 55 \mathrm{Cs}\) (D) \({ }^{16}{ }_{8} \mathrm{O}\)

Nucleon is common name for (A) electron and neutron (B) proton and neutron (C) neutron and positron (D) neutron and neutrino

The wave length of the first line of Lyman series for hydrogen atom is equal to that of hydrogen atom is equal to that of second line of Balmar series for a hydrogen like ion. The atomic number \(\mathrm{Z}\) of hydrogen like ion is (A) 1 (B) 2 (C) 3 (D) 4
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