Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 18: Problem 2535

\({ }_{6} \mathrm{C}^{12}\) absorbs an energetic neutron and emits a \(\beta\) Particle. The resulting nucleus is (A) \({ }_{7} \mathrm{~N}^{13}\) (B) \({ }_{7} \mathrm{~N}^{14}\) (C) \({ }_{6} \mathrm{C}^{13}\) (D) \({ }_{6} \mathrm{C}^{12}\)

Short Answer

Expert verified
The resulting nucleus after the absorption of a neutron and emission of a beta particle is \({ }_{7} \mathrm{N}^{13}\). The correct answer is option (A).

Step by step solution

01

Identify the initial nucleus

The initial nucleus given in the problem is Carbon-12, which can be written as \({ }_{6} \mathrm{C}^{12}\). This means that it has 6 protons and 6 neutrons (12-6=6).
02

Absorption of a neutron

When the Carbon-12 nucleus absorbs a neutron, its neutron count increases by 1. So, the new nucleus will have 6 protons and 7 neutrons, making it Carbon-13 (\({ }_{6} \mathrm{C}^{13}\)).
03

Emission of a beta particle

A beta particle is an electron that is emitted during a beta decay process, in which a neutron changes into a proton. In this reaction, one of the 7 neutrons will change into a proton, so the resulting nucleus will have 7 protons and 6 neutrons (7+6=13).
04

Identify the final nucleus

The final nucleus will have 7 protons and 6 neutrons, which corresponds to Nitrogen-13. Hence, the resulting nucleus after the absorption of a neutron and emission of a beta particle is \({ }_{7} \mathrm{N}^{13}\). So, the correct answer is option (A) \({ }_{7} \mathrm{~N}^{13}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In gamma ray emission form a nucleus (A) there is no change in the proton-number and neutron number (B) Both the number are changes (C) only Proton number change (D) only neutron number change

Match column I and II and chose correct Answer form the given below. (a) Nuclear fusion (p) converts some matter into energy (b) Nuclear fission (q) generally Possible for nuclei with low atomic number (c) \(\beta\) decay (r) generally Possible for nuclei with high atomic number (d) Exothermic nuclear (s) Essentially Proceeds by weak reaction nuclear force(c) (A) $\mathrm{a} \rightarrow \mathrm{p}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{q}$ (B) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{d} \rightarrow \mathrm{s}$ (C) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{p}$ (D) $\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{q}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{d} \rightarrow \mathrm{s}$

Radio carbon dating is done by estimating in the specimen (A) the amount of ordinary carbon still present (B) the ratio of the amounts of \({ }^{14}{ }_{6} \mathrm{C}\) to ${ }_{6} \mathrm{C}^{12}$ (C) the amount of radio carbon still Present (D) None of these

A Free neutron decays into a Proton, an electron and (A) \(\mathrm{v}\) (B) \(\underline{\mathrm{V}}\) (C) \(\beta\) (D) \(\alpha\)

The ratio of atomic volume of nuclear volume is of the order of (A) \(10^{-15}\) (B) \(10^{-10}\) (C) \(10^{15}\) (D) \(10^{-10}\)
See all solutions

Recommended explanations on English Textbooks

Lexis and Semantics

Read Explanation

Lexis and Semantics Summary

Read Explanation

Essay Plan

Read Explanation

Essay Writing Skills

Read Explanation

Language Analysis

Read Explanation

Free Response Essay

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free