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Chapter 19: Problem 2598

In a common emitter amplifier, output resistance is \(5000 \Omega\) and input resistance is \(1000 \Omega .\) If peak value of signal voltage is $1 \mathrm{mV}\( and \)\beta=100$, then the peak value of output voltage is (A) \(0.1 \mathrm{~V}\) (B) \(0.3 \mathrm{~V}\) (C) \(0.2 \mathrm{~V}\) (D) \(0.5 \mathrm{~V}\)

Short Answer

Expert verified
The peak value of output voltage is \(0.5 V\).

Step by step solution

01

Understand the Given Data

The provided data includes: - Output resistance, \(R_o = 5000 \Omega\), - Input resistance, \(R_i = 1000 \Omega\), - Peak value of signal voltage, \(V_s = 1mV\) = \(0.001V\), - Beta, \(\beta = 100\) (current gain).
02

Calculate Voltage Gain

With these values, you can calculate the voltage gain \(A_v\). Using the formula \(A_v=\beta \frac{R_o}{R_i}\), \(A_v=100 \left(\frac{5000}{1000}\right)\) which simplifies to \(A_v=500\).
03

Calculate Output Peak Voltage

Finally, the peak output voltage (\(V_o\)) can be determined by multiplying the voltage gain by the peak signal voltage. The formula is \(V_o= A_v \cdot V_s\). Substituting the values, we get \(V_o= 500 \cdot 0.001V = 0.5V\), indicating that option (D) \(0.5 V\) is the correct answer.

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