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Chapter 19: Problem 2618

To obtain OR gate from NOR gate, you will need (A) one NOR gate (B) one NOT gate (C) Two NOR gate (D) one OR gate

Short Answer

Expert verified
The correct choice to obtain an OR gate from NOR gates is (C) Two NOR gates.

Step by step solution

01

Understand OR and NOR Gates

The OR gate is a digital logic gate that implements logical disjunction. It gives an output of 1 (true) if at least one of its inputs is 1 (true). Its symbol and truth table are as follows: OR gate: Input A | Input B | Output --------|---------|------- 0 | 0 | 0 0 | 1 | 1 1 | 0 | 1 1 | 1 | 1 The NOR gate is a digital logic gate that implements the "NOT OR" function, which means its output will be the inverted output of OR gate. Its symbol and truth table are: NOR gate: Input A | Input B | Output --------|---------|------- 0 | 0 | 1 0 | 1 | 0 1 | 0 | 0 1 | 1 | 0
02

Obtain OR gate from NOR gates

To obtain an OR gate using NOR gates, we will require two NOR gates. The output of the first NOR gate will be inverted, and as a result, we'll obtain the desired OR gate output. The configuration will look like this: Input A --NOR1--> --NOR2--> Output Input B ---------/ The truth table for this configuration would be: Input A | Input B | NOR1 Out | OR Out (NOR2) --------|---------|----------|------------- 0 | 0 | 1 | 0 0 | 1 | 0 | 1 1 | 0 | 0 | 1 1 | 1 | 0 | 1 As we can see, the output of the combined NOR gates matches the truth table of an OR gate.
03

Analyze the given options

Now, let's analyze each option: (A) one NOR gate: Although NOR gate is closely related to OR gate, it cannot be used directly to obtain the OR gate functionality. (B) one NOT gate: A NOT gate alone cannot provide the function of an OR gate as it just inverts the input. (C) Two NOR gate: As shown in the configuration above, using two NOR gates correctly connected, we can achieve the behavior of an OR gate. (D) one OR gate: Obtaining an OR gate from an OR gate is trivial and not a valid option in this context. After analyzing each option, the correct answer becomes apparent:
04

Correct Choice

The correct choice to obtain an OR gate from NOR gates is (C) Two NOR gates.

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Most popular questions from this chapter

A potential barrier of \(0.6 \mathrm{~V}\) exists across a P-N junction. If the depletion region is \(1 \mu \mathrm{m}\) wide, what is the intensity of electric field in the region? (A) \(4 \times 10^{5} \mathrm{Vm}^{-1}\) (B) \(5 \times 10^{5} \mathrm{Vm}^{-1}\) (C) \(6 \times 10^{5} \mathrm{Vm}^{-1}\) (D) \(2 \times 10^{5} \mathrm{Vm}^{-1}\)

For Boolean identities match the pair: (1) \(\underline{\underline{A}}\) (P) \(\underline{\mathrm{A}}+\underline{\mathrm{B}}\) (2) \(\underline{\mathrm{A}+\mathrm{B}}\) (Q) A \cdot B (3) \(\underline{\mathrm{A} \cdot \mathrm{B}}\) (R) \(\underline{A} \cdot \underline{B}\) (4) \(\mathrm{A} \cdot(\underline{\mathrm{A}}+\mathrm{B})\) (S) \(\mathrm{A}\) (A) \((1)-(\mathrm{S}),(2)-(\mathrm{P}),(3)-(\mathrm{Q}),(4)-(\mathrm{R})\) (B) \((1)-(\mathrm{S}),(2)-(\mathrm{R}),(3)-(\mathrm{Q}),(4)-(\mathrm{P})\) (C) (1) - (S), (2) - (Q), (3) - (P), (4) - (R) (D) \((1)-(\mathrm{S}),(2)-(\mathrm{R}),(3)-(\mathrm{P}),(4)-(\mathrm{Q})\)

A n-p-n transistor is used in common emitter made in an amplifier it. A change of \(40 \mu \mathrm{A}\) in the base current changes the output current by $2 \mathrm{~mA}\( and \)0.04 \mathrm{~V}$ in input voltage. The current amplification factor is (A) 20 (B) 30 (C) 50 (D) 400

Which of the following logic gate will have output \(1 ?\)

Direction for Assertion - Reason type questions (A) If both Assertion and Reason are true and reason is the correct explanation of assertion. (B) If both Assertion and Reason are true but Reason is not the correct explanation of assertion. (C) If Assertion is true but Reason is false (D) If both assertion and reason are false A : A transistor amplifier circuit in common emitter configuration has low input impedance \(\mathrm{R}\) : Base-emitter junction is forward biased (A) (B) (C) (D)
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